A company borrows $50,000 at 6% for 6 months. Find the amount of simple interest that

Divide the polynomial x^3+x^2-2x+3 by (x-1)

Anni [7]

Answer:

x² + 2x + (3 / (x − 1))

Step-by-step explanation:

Start by setting up the division:

.........____________

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³. Divided by x, that's x². So:

.........____x²______

x − 1 | x³ + x² − 2x + 3

Multiply x − 1 by x², subtract the result, and drop down the next term:

.........____x²______

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Repeat the process over again. First term is 2x². Divided by x is 2x. So:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Multiply, subtract the result, and drop down the next term:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

.................-(2x² − 2x)

.................---------------

.....................................3

x doesn't divide into 3, so that's the remainder.

Therefore, the answer is:

x² + 2x + (3 / (x − 1))

8 0

2 years ago

Steve,Jerry and Ron were paid $29.25 to remove garden gnomes. They each worked 4 hours, exempt for Ron, who was 1 hour late. How

Alenkasestr [34]

Ron should receive $7.98. Jerry and Steve each worked for 4 hours, while Ron was one hour late, so he worked for 3 hours. Together, they worked for 4*2+3=11 hours, receiving $29.25 in total. Each hour should be paid 29.25/11=2.66 dollars. Ron worked for three hours, so he should receive 3*2.66=7.98 dollars.

5 0

3 years ago

Can someone give me an example on a Riemann Sum and like how to work through it ? I want to learn but I don’t understand it when

Georgia [21]

Explanation:

A Riemann Sum is the sum of areas under a curve. It approximates an integral. There are various ways the area under a curve can be approximated, and the different ways give rise to different descriptions of the sum.

A Riemann Sum is often specified in terms of the overall interval of "integration," the number of divisions of that interval to use, and the method of combining function values.

Example Problem

For the example attached, we are finding the area under the sine curve on the interval [1, 4] using 6 subintervals. We are using a rectangle whose height matches the function at the left side of the rectangle. We say this is a left sum.

When rectangles are used, other choices often seen are right sum, or midpoint sum (where the midpoint of the rectangle matches the function value at that point).

Each term of the sum is the area of the rectangle. That is the product of the rectangle's height and its width. We have chosen the width of the rectangle (the "subinterval") to be 1/6 of the width of the interval [1, 4], so each rectangle is (4-1)/6 = 1/2 unit wide.

The height of each rectangle is the function value at its left edge. In the example, we have defined the function x₁(j) to give us the x-value at the left edge of subinterval j. Then the height of the rectangle is f(x₁(j)).

We have factored the rectangle width out of the sum, so our sum is simply the heights of the left edges of the 6 subintervals. Multiplying that sum by the subinterval width gives our left sum r₁. (It is not a very good approximation of the integral.)

The second and third attachments show a right sum (r₂) and a midpoint sum (r₃). The latter is the best of these approximations.

_____

Other Rules

Described above and shown in the graphics are the use of rectangles for elements of the summation. Another choice is the use of trapezoids. For this, the corners of the trapezoid match the function value on both the left and right edges of the subinterval.

Suppose the n subinterval boundaries are at x0, x1, x2, ..., xn, so that the function values at those boundaries are f(x0), f(x1), f(x2), ..., f(xn). Using trapezoids, the area of the first trapezoid would be ...

a1 = (f(x0) +f(x1))/2·∆x . . . . where ∆x is the subinterval width

a2 = (f(x1) +f(x2))/2·∆x

We can see that in computing these two terms, we have evaluated f(x1) twice. We also see that f(x1)/2 contributes twice to the overall sum.

If we collapse the sum a1+a2+...+an, we find it is ...

∆x·(f(x0)/2 + f(x1) +f(x2) + ... +f(x_n-1) + f(xn)/2)

That is, each function value except the first and last contributes fully to the sum. When we compute the sum this way, we say we are using the trapezoidal rule.

If the function values are used to create an approximating parabola, a different formula emerges. That formula is called Simpson's rule. That rule has different weights for alternate function values and for the end values. The formulas are readily available elsewhere, and are beyond the scope of this answer.

_____

Comment on mechanics

As you can tell from the attachments, it is convenient to let a graphing calculator or spreadsheet compute the sum. If you need to see the interval boundaries and the function values, a spreadsheet may be preferred.

8 0

2 years ago

Consolidated Power, a large electric power utility, has just built a modern nuclear power plant. This plant discharges waste wat

Gemiola [76]

Answer:

We conclude that the plant should shut down.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 60

Sample mean, $\bar{x}$ = 61.498

Sample size, n = 100

Alpha, α = 0.05

Population standard deviation, σ = 6

a) First, we design the null and the alternate hypothesis such that the power plant will be shut down when the null hypothesis is rejected.

$H_{0}: \mu \leq 60\\H_A: \mu > 60$

We use One-tailed(right) z test to perform this hypothesis.

b) Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{61.498 - 60}{\frac{6}{\sqrt{100}} } = 2.49$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.

Calculating the p-value from the z-table:

P-value = 0.0063

Since,

P-value < Significance level

We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.

7 0

3 years ago

paco has 75 minutes before he needs to get ready for baseball practic.he cleans his room for 40 minutes and reads and reads for

fomenos

By the way this problem is worded, he spends 75 minutes reading and cleaning, but there seems to be not enough information because the way it is worded, it means he has 75 minutes until he needs to GET READY, not play in the actual game. (40 + 35 = 75).

3 0

2 years ago