Answer:
The player throws 127.3 ft from second base to home plate.
Step-by-step explanation:
Given:
Distance from home to first base = 90 ft
Distance from first base to second base = 90 ft
We need to find the distance from second base to home.
Solution:
Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.
Now by using Pythagoras theorem which states that;
Square of the hypotenuse side is equal to sum of squares of other two sides.
framing in equation form we get;
distance from second base to home = 
Rounding to nearest tent we get;
distance from second base to home = 127.3 ft
Hence The player throws 127.3 ft from second base to home plate.
The first answer is 9x + 2y
the second answer is 3y
The unit rate is 2/3 because in the line y=2/3x, 2/3 is the slope (y=mx+b). The slope of the line is pretty much the definition of a unit rate because the unit rate is a constant addition or subtraction over and over. In addition, it is a straight line(y=mx+b) and the values are going up at a constant rate of 2/3.
Answer: y = (-4/5)x + 8
Solution
The equation of line is
y = mx + b
Where
y = y coordinate
m = slope
x = x coordinate
b = y intercept
In order to write the equation of line we need to find the y-intercept (b)
substitute the slope (-4/5) and coordinates given (0,8) ,
y = mx + b
8 = -4/5 (0) + b
8 = b
So,
y = (-4/5)x + 8
Step-by-step explanation:
Hey there!
By looking through figure, l and m are parallel lines and a transversal line passes through the lines.
Now,
7x + 12° = 12x - 28°( alternate angles are equal)
12°+28° = 12x - 7x
40° = 5x

Therefore, x = 8°
Now,
12x - 28° + 9y - 77 = 180° ( being linear pair)
12×8° - 28° + 9y -77° = 180°
96° - 28° + 9y - 77° = 180°
-9 + 9y = 180°
9y = 180° + 9°
y = 189°/9
Therefore, y = 21°
<u>There</u><u>fore</u><u>,</u><u> </u><u>X </u><u>=</u><u> </u><u>8</u><u>°</u><u> </u><u>and</u><u> </u><u>y</u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u><u> </u><u>.</u>
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>