I think that the answer is D
t = t₀ / 2
Explanation:
In this exercise we must use Newton's second law
F = m a
a = F / m
now we can use kinematics
as in object part of rest (v₀ = 0)
v =a t₀
t₀ = v / a
these results are with the first experiment
now repeat the experiment, but F = 2F₀
a = 2F₀ / m = 2 a₀
v = 2 a₀ t
t = v / 2a₀
t = t₀ / 2
A triangle has vertices at b(−3, 0), c(2, −1), d(−1, 2). which series of transformations would produce an image with vertices b″(4, 1), c″(−1, 0), d″(2, 3)? (x, y) → (x, −y), (x, y) → (x + 1, y + 1) (x, y) → (−x, y), (x, y) → (x + 1, y + 1) (x, y) → (x, −y), (x, y) → (x + 2, y + 2) (x, y) → (−x, y), (x, y) → (x + 2, y + 2)
The answer is B