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3 years ago

A pair of vertical angles has measures (2y + 5) and (4y) What is the value of y?

Mathematics

1 answer:

iogann1982 [59]3 years ago

8 0

Answer:

Vertical angles are angles that are opposite each other when two lines intersect each other. And they are always equal.

==> 2y +5 = 4y

==> 4y - 2y = 5

==> 2y = 5

==> $y = \frac{5}{2}$

Option D

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Which statement about the equation 3x ^ 2 + 9x - 12 = 0 is true ? 1 . The product of the roots is -12 . 2 The product of the roo

svetlana [45]

Answer:

Option : The product of the roots is - 4

Step-by-step explanation:

$3x^2 + 9x - 12 = 0\\\\3x^2 + 12x - 3x - 12 = 0\\\\3x(x+4) -3(x+4) = 0\\\\(3x - 3) (x+ 4) = 0\\\\$

Therefore the roots are -4 and 1

The product of the roots are -4 x 1 = -4

5 0

3 years ago

Given that f(x) = 2x + 1 and g(x) = −5x + 2, solve for f(g(x)) when x = 3.

ANTONII [103]

$f(x)=2x+1 \\
g(x)=-5x+2 \\ \\
f(g(x))=2(-5x+2)+1=-10x+4+1=-10x+5 \\
f(g(3))=-10 \times 3+5=-30+5=-25 \\
\boxed{f(g(3))=-25}$

The answer is C.

4 0

3 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

Which value would make the inequality true?

nata0808 [166]

Answer:

Step-by-step explanation:

Hope this helps. . .

5 0

2 years ago

Read 2 more answers

cynthia besch wants to buy a rug for a room that is 14ft wide and 23 ft long. She wants to leave a uniform strip of floor around

choli [55]

The room is 14w and 23 l

she can buy up to 190 sqft

190 factors into 10 and 19

14 - 10 = 4
23 - 19 = 4
Which are uniform

so the answer is 10 ft wide and 19 ft long

Hope this helps

8 0

3 years ago