Answer:
(a) α = 60°, β = 30°
(b) α ≈ 67.4°, β ≈ 22.6°
Step-by-step explanation:
I'll do (a) and (b) as examples. Make sure your calculator is set to degrees, not radians.
(a) For α, we're given the opposite and adjacent sides, so use tangent.
tangent = opposite / adjacent
tan α = √300 / 10
tan α = √3
α = 60°
Since angles of a triangle add up to 180°, we know that β = 30°. But we can use tangent again to prove it:
tan β = 10 / √300
tan β = 1 / √3
tan β = √3 / 3
β = 30°
(b) For α, we're given the adjacent side and the hypotenuse. So use cosine.
cos α = adjacent / hypotenuse
cos α = 15 / 39
cos α = 5 / 13
α ≈ 67.4°
Again, we know that β = 22.6°, but let's show it using trig. We're given the opposite side and hypotenuse, so use sine:
sin β = 15 / 39
sin β = 5 / 13
β ≈ 22.6°
Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
Answer:
is it multiple answer?
Step-by-step explanation:
