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Dahasolnce [82]

3 years ago

9

If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

1 answer:

Ilya [14]3 years ago

6 0

Answer:

<em>A) The x-intercept decreases. </em>

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em> Consider the function f(x) = mx + b, where m > 0. </em>

<em>If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept? </em>

<em>A) The x-intercept decreases. </em>

<em>B) The x-intercept increases. </em>

<em>C) The x-intercept approaches zero. </em>

<em>D) The x-intercept remains the same </em>

Here is my answer:

Given the function f(x) = mx + b, where m > 0.

x-intercept happen when y =0

When b decreases and m stay the same, the value of f(x) will be decreased. For example: f(x)= 2x + 3 = 0

When b unchanged, m unchanged we have: 2x + 3 = 0 <=> x = -3/2

When b decreases to 2, m unchanged we have: 2x + 2 = 0 <=> x = -1

Obviously that, -1 < -3/2 so the x-intercept will be decreased

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Point B has coordinates (-2,-5). After a translation 4 units down, a reflection across the y-axis, and a

Ratling [72]

Answer:

2, -3

Step-by-step explanation:

4 units down is -9, then a reflection over y axis makes -2 2 6 units up makes -9 -3

5 0

3 years ago

The equation of line v is y = -x + 9. Line w, which is perpendicular to line v, includes the

Oduvanchick [21]

Answer:

y=x+1

Step-by-step explanation:

In order to find the slope that is perpendicular to a given line, you have to take the fraction form (-1/1), flip it (1/-1), and give it an opposite sign (1/1). Now since we now know our slope we can draw y=x to find what do we have to add. Since y=x crosses (2,2), we know we have to add 1 to the equation in order to bring it to (2, 3).

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3 years ago

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V125BC [204]

Answer:

1. I am not sure about the first one. I tried everything and nothing I got from any of my work is looking right.

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4 0

3 years ago

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0

3 years ago

Read 2 more answers

Hypothesis Testing for Means with Small Samples

Scorpion4ik [409]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: volume of root beer in a Windsor Bottling Company can.

A sample of n=24 cans was taken and their contents measured, resulting:

X[bar]= 11.4 oz

S= 0.62 oz

Assuming that the variable has a normal distribution X~N(μ;σ²), the parameter of interest is the average contents of the root beer cans of the Windsor Bottling Company (μ)

The claim is that the population mean content of the cans is different from 12 oz, symbolically: μ ≠ 12

The statistical hypothesis (Null and alternative) have to be complementary, exhaustive and mutually exclusive. The null hypothesis is the "no change" hypothesis and always carries the "=" sign.

If the claim is μ ≠ 12, its complement is μ = 12, the expression carrying the "=" sign will be the null hypothesis and its complement will be the alternative hypothesis:

H₀: μ = 12

H₁: μ ≠ 12

α: 0.05

To test the population mean of this normal population, you have to apply a one sample t-test, with statistic:

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

$t_{H_0}= \frac{11.4-12}{\frac{0.62}{\sqrt{24} } } = -4.74$

This test is two-tailed, using the critical value approach, you have to determine two rejection regions. Meaning, you'll reject the null hypothesis to small values of the statistic or to high values of the statistic.

$t_{n-1;\alpha /2}= t_{23;0.025}= -2.069$

$t_{n-1;1-\alpha /2}= t_{23;0.975}= 2.069$

The decision rule is:

If $t_{H_0}$ ≤ -2.069 or if $t_{H_0}$ ≥ 2.069, then you reject the null hypothesis.

If -2.069 < $t_{H_0}$ < 2.069, then you do not reject the null hypothesis.

The value is less than the left critical value, the decision is to reject the null hypothesis.

Then you can say that with a 5% significance level, there is significant evidence to reject the null hypothesis, then the average amount of root beer of the Windsor Bottling Company is different from 12 oz, this means that the claim about the amount of root beer in the cans is correct.

I hope it helps!

6 0

3 years ago