Answer:
<em>A) The x-intercept decreases.
</em>
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>
Consider the function f(x) = mx + b, where m > 0.
</em>
<em>If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?
</em>
<em>A) The x-intercept decreases.
</em>
<em>B) The x-intercept increases.
</em>
<em>C) The x-intercept approaches zero.
</em>
<em>D) The x-intercept remains the same
</em>
Here is my answer:
Given the function f(x) = mx + b, where m > 0.
x-intercept happen when y =0
When b decreases and m stay the same, the value of f(x) will be decreased. For example: f(x)= 2x + 3 = 0
When b unchanged, m unchanged we have: 2x + 3 = 0 <=> x = -3/2
When b decreases to 2, m unchanged we have: 2x + 2 = 0 <=> x = -1
Obviously that, -1 < -3/2 so the x-intercept will be decreased
