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RUDIKE [14]
3 years ago
15

What are the removable discontinuities of the following function? f (x) = startfraction x squared minus 36 over x cubed minus 36

x endfraction x = –6, x = 0, and x = 6 x = –6 and x = 6 x = 0 and x = –6 x = 0 and x = 6
Mathematics
1 answer:
Lyrx [107]3 years ago
8 0

The removable discontinuity is at negative 6 and 6. Then the correct option is B.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

The function is given as

f\rm (x) =\rm  \dfrac{x^2-36}{x^3-36x}

The expression can be written as

f\rm (x) =\rm  \dfrac{x^2-36}{x(x^2-36)}

f\rm (x) = \dfrac{1}{x}

The non-removable discontinuity is x = 0.

More about the function link is given below.

brainly.com/question/5245372

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Llana [10]

Answer:

1131.0 m^3

Step-by-step explanation:

Let h1 represent the height of the top cone, and h2 the height of the bottom cone. The volume of a cone is given by the formula ...

V = (1/3)πr^2·h

so the volumes of both cones together will be ...

V = (1/3)πr^2·h1 + (1/3)πr^2·h2 = (1/3)πr^2·(h1 +h2)

= (1/3)π(6 m)^2(12 m + 18 m) = 360π m^3

≈ 1131.0 m^3

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Ksju [112]
The answer is $3.75.

6 0
3 years ago
PLEASE HELP ASAP !!!! WILL MARK BRAINLIEST
kakasveta [241]

Answer:

10

Step-by-step explanation:

We can write the equation 38=4y-2 because LZ and DO are equivalent

Isolate x:

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40/4=4y/4 (divide by 4, division property of equality)

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3 0
3 years ago
Consider the diagram and the paragraph proof below. Given: Right △ABC as shown where CD is an altitude of the triangle Prove: a2
gladu [14]
The answer is B.

This is because since f + e = c,
then a² + b² = c(f + e)
a² + b² = c(c)
a² + b² = c²

This is the correct answer 
5 0
3 years ago
Read 2 more answers
What is the domain and range and function ??? Then can u explain how u did it please and thank you
enot [183]
The domain is
- 10 \leqslant x \leqslant 10
and the range is
- 5 \leqslant y \leqslant 5
Domain is x values (horizontal axis), while range is y values (vertical axis). On a line like this one, domain is calculated from the left most point to the right most, while range is calculated from the down most to the upmost.
Because this line is a solid line rather than a dotted line, less than or equal to
\leqslant
signs are used rather than just
<
less than signs.


6 0
3 years ago
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