3 years ago

Factorize 27a³-b³-1-9ab

Mathematics

2 answers:

victus00 [196]3 years ago

7 0

Answer:

Hope this helps!

Please see through the steps below

Elis [28]3 years ago

6 0

Answer:

<u>Use the following identity:</u>

a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c²- ab - bc - ca)

<u>Apply to the given:</u>

27a³ - b³ - 1 - 9ab =
(3a)³ + (-b)³ + (-1)³ - 3*3a*(-b)(-1) =
(3a - b - 1)(9a² + b² + 1 + 3ab - b + 3a)

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