Answer:
a) 0.5198 mol/L
b) 0.00811 mol KOH
Explanation:
a) M(KOH) = 39+16+1= 56 g/mol
14.555g* 1 mol/56 g = 14.555/56 mol KOH in 500.0 mL solution
14.555/56 mol KOH ---- 0.5000 L solution
x mol KOH ----- 1 L solution
x = (14.555/56)mol * 1L/0.5000 L = 0.5198 mol/L
b) If the student pours out a 15.6 mL sample of this solution, how many moles of sodium hydroxide? (if we talk about KOH)
does the student have in the sample
15.6 mL = 0.0156 L
0.5198 mol/L * 0.0156 L = 0.00811 mol KOH
Answer:
Explanation:
Hello!
In this case, since the undergoing chemical reaction is:
It is widely known that when a gas given off from a reaction is collected over water, we can compute its pressure by minusing the total pressure 762 mmHg and the vapor pressure of water at the experiment's temperature (20 °C) in this case 17.5 mmHg as shown below:
Next, by using the ideal gas equation we compute the yielded moles of oxygen considering the collected 313 mL (0.313 L):
Now, via the 3/2:1 mole ratio between oxygen and lithium chlorate (molar mass = 90.39 g/mol), we compute the original mass of decomposed lithium chlorate as follows:
Now, the percentage is computed as shown below:
Best regards!
Answer:
Sn(C2H3O2)2
Explanation:
C2H3O2 is Acetate
Sn is tin
Acetate has a -1 charge
In order for tin to have a +2 charge, we need two acetates
So we write it as (C2H3O2)2
You just leave Sn blank because of the roman numeral and since it is a transition metal.
So the answer is Sn(C2H3O2)2
Answer:
I think it’s the first one, holly ferns sorry if I’m wrong!