Answer: option B and option C
Explanation:
The answer is 62.00 g/mol.
Solution:
Knowing that the freezing point of water is 0°C, temperature change Δt is
Δt = 0C - (-1.23°C) = 1.23°C
Since the van 't Hoff factor i is essentially 1 for non-electrolytes dissolved in water, we calculate for the number of moles x of the compound dissolved from the equation
Δt = i Kf m
1.23°C = (1) (1.86°C kg mol-1) (x / 0.105 kg)
x = 0.069435 mol
Therefore, the molar mass of the solute is
molar mass = 4.305g / 0.069435mol = 62.00 g/mol
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Chromatography is used in purification. Drugs analysts may use the technique to separate the active molecule in a drug molecule, for efficacy or toxicity analysis, from the other drug components.
Explanation:
Chromatography is used to separate a mixture of different components based on the size of their molecules. In liquid chromatography, the mixture is dissolved in a solvent that acts as the mobile phase and then passed along a stationary phase with different kinds of pores, As the mixture passes through the pores, their different components are separated because they take different times to pass through the stationary phase because of their different rates in passing through the pores.
In gas chromatography, a gas is used as a mobile phase while a liquid is used as the stationary phase.
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Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :

Now, n-factor is :

Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃