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irakobra [83]
3 years ago
12

A sound wave traveling through a certain freshwater lake has a frequency of 349.2 Hz and a wavelength of 4.25 m. What is the spe

ed of a sound wave in this water? (Round your answer to three significant figures.)
Chemistry
2 answers:
erica [24]3 years ago
7 0

Answer:

ν = 1483.939 m/s

Explanation:

Wave propagation speed (ν):

  • ν = λ / T

∴ Wavelength ( λ ) = 4.25 m

∴ Period ( T ) = 1 / f

∴ frequency ( f ) = 349.2 Hz ( s-1 )

⇒ T = 1 / 349.2 s-1

⇒ T = 2.864 E-3 s

⇒ ν = (4.25 m) / (2.864 E-3 s)

⇒ ν = 1483.939 m/s

kramer3 years ago
6 0

<u>Answer:</u> The wave speed of the given sound wave is 1.48\times 10^3m/s  

<u>Explanation:</u>

Wave speed is defined as the product of its wavelength and frequency.

Mathematically,

\text{Wave speed}=\lambda\times \nu

where,

\lambda = wavelength of the wave = 4.25 m

\nu = frequency of the wave = 349.2 Hz = 349.2s^{-1}

Putting values in above equation, we get:

\text{Wave speed}=4.25m\times 349.2s^{-1}\\\\\text{Wave speed}=1484.1m/s=1.48\times 10^3m/s

Hence, the wave speed of the given sound wave is 1.48\times 10^3m/s

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<u>Answer:</u> The pH of the solution is 9.71

<u>Explanation:</u>

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

pOH of the solution = 7.2

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=5.09\times 10^{-5}M

Putting values in above equation, we get:

pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4.29=9.71

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3 years ago
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kolbaska11 [484]

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Answer:

answer-

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Answer : The correct option is, (3) change states of matter.

Explanation :

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Latent heat of fusion : It is defined as the amount of heat energy released or absorbed when the solid converted to liquid at atmospheric pressure at its melting point.

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Answer:

True

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