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slega [8]
3 years ago
12

Helpppp meeeee pleaseee

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0
18 I’m pretty sure that is the answer that
U want
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Can someone please please help me on this algebra problem I’m stuck on answering the question?
Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}

Answer: Midline=1

1) Amplitude

\text{Amplitude =}2

2) Periods

\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}

4) The trigonometric equation is,

\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}

Answer:

y=2\cos (\frac{2\pi}{6}x)+1

4 0
1 year ago
Factor 3y3 – 9y2<br> The factored polynomial is
allochka39001 [22]

Answer:

Factor 3y23y2 out of 3y33y3.

3y2(y)−9y23y2(y)-9y2

Factor 3y23y2 out of −9y2-9y2.

3y2(y)+3y2(−3)3y2(y)+3y2(-3)

Factor 3y23y2 out of 3y2(y)+3y2(−3)3y2(y)+3y2(-3).

3y2(y−3)

Step-by-step explanation:

mark me the brainliest please

4 0
4 years ago
What is happening to this graph when the x values are between -1 and 1
Amiraneli [1.4K]
It is decreasing, since the y-value is going down.
3 0
3 years ago
Read 2 more answers
What is the area of this parallelogram? A 10.35 cm2 B 12.5 cm2 C 20.25 cm2 D 30.6 cm2​
sveta [45]
The answer would be D.
6 0
3 years ago
Read 2 more answers
In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria
Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

P(t)=ae^{rt}\\\\where\ t\ is\  the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start

At 2 hours, the population is 62 cells, hence:

P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)

After another 2 hours (4 hours), the population is 1 million:

P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844

Put r = 4.844 in equation 1

62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844

P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844

4 0
3 years ago
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