Leonard total purchase is $520,452.
The correct option is (C)
<h3>What is Unitary method?</h3>
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value
Given:
There are 61 new Ford Transits.
If each Ford Transit costs Leonard $8,532.
Then, total purchasing will be
=8532*61
= $520,452.
Hence, Leonard total purchase is $520,452.
Learn more about this concept here:
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Here we have a problem of probability, we will find that the probability of landing in heads is M/N = 1/3, then we have:
M + N = 1 + 3 = 4.
Let's see how we got that:
Let's define:
p = probability of landing on tails
q = probability of landing on heads.
The probability of getting at least one tails in 3 tosses is 26/27
This means that the probability of not getting tails in the 3 tosses is:
P = 1 - 26/27 = 1/27
And the case where you do not get any tails in the 3 tosses, means that in all the 3 tosses you got heads.
The probability of getting 3 heads in a row is:
P = q^3 = 1/27
Solving for q, we get:
q = ∛(1/27) = 1/3
Now we want to express q = M/N = 1/3
then we have:
M = 1
N = 3
Now we want to compute M + N = 1 + 3 = 4
If you want to learn more about probability, you can read:
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Answer: The answers for both (a) and (b) is YES.
Step-by-step explanation: A polynomial is an algebraic expression containing two or more algebraic terms, i.e., the sum of several terms that contain different powers of the same variable or variables with real coefficients.
For example, p(x) = 4x²+x+2 is a polynomial in variable 'x'.
(a) Yes, the sum of two polynomials is again a polynomial. For example,
if p(x) = ax² + bx + c and q(x) = dx² + ex + f, where, a, b, c, d, e and f are real numbers, then their sum will be
p(x) + q(x) = (a+d)x²+(b+e)x+(c+f), which is again a polynomial in 'x' with real coefficients.
(b) Yes, the difference of two polynomials is again a polynomial. For example,
p(x) - q(x) = (a-d)x²+(b-e)x+(c-f), which is again a polynomial in 'x' with real coefficients.
Thus, the answer is YES.
There are 76200000 or 762 x 10^5 more people in Mexico than Canada.