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scoundrel [369]
3 years ago
7

Help.help.help.help.help lol but i need help on this as quick as possible:)

Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

The 3rd graph goes on top, the 2nd graph stays in the middle, and the 1st graph goes on the bottom

Step-by-step explanation:

you are sorting these graphs by which people are getting the most average sleep. The people with less sleep go on top while the people with more sleep go on the bottom. You will find the mean (average) for each graph and sort them out.

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5. If "h" is positive how does the parabola move? If negative?
Paul [167]

Answer: positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

Step-by-step explanation: Note that the value for h is subtracted from x, and then this difference is squared. See that positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

7 0
3 years ago
Multiply.<br><br><br><br> –58.7 • 13<br><br><br> Divide.<br><br> -6 ÷ 1/4
Vitek1552 [10]
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3 years ago
Solve the equation as shown 2(x+6) = 22
lutik1710 [3]

Answer:

x = 5

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6 0
3 years ago
Read 2 more answers
The perimeter of a square is proportional to the length of its sides. This relationship can be expressed by the equation p=4s. W
stealth61 [152]
Constant of proportionality is the constant value of the two proportional quantities, in this problem p and s, where 4 is the factor of proportionality because it is constant or k.

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In the above problem, the number 4 is derived from the word square. We all know that a square has 4 sides of equal lengths, therefore, the perimeter is equivalent to the product of 4 and its lenght.
3 0
3 years ago
Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

7 0
2 years ago
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