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Lesechka [4]
2 years ago
13

What is the volume of a sphere with a radius of 8 m, rounded to the nearest tenth of a cubic meter?

Mathematics
1 answer:
zlopas [31]2 years ago
6 0
<h3>given:</h3>

radius= 8 m

<h3>to find:</h3>

the volume of the sphere

<h3>solution:</h3>

v =  \frac{4}{3} \pi {r}^{3}

v =  \frac{4}{3}  \times \pi \times  {8}^{3}

v = 2144.66058 \:  {m}^{3}

v = 2144.7 \:  {m}^{3}

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>sphere</u><u> </u><u>is</u><u> </u><u>2144.7</u><u> </u><u>cubic</u><u> </u><u>meters</u><u>.</u>

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Jason saved gas money (x).  Maria saved $20 more than double what Jason has (20 + 2x).  Combined, they saved $200.  Solve for x for Jason's amount.

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Work out the surface area of a cylinder when the height = 18cm and the volume = 1715cm cubed
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813.4 cm² (nearest tenth)

Step-by-step explanation:

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

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Use the Volume of a Cylinder formula and the given values to find the <u>radius of the cylinder</u>:

\implies \sf 1715=\pi r^2 (18)

\implies \sf r^2=\dfrac{1715}{18 \pi}

\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}

<u>Surface Area of a Cylinder</u>

\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}

Substitute the given value of h and the found value of r into the formula and solve for SA:

\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)

\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

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