Answer:
Depends, but is either 24, 362880, and 5040, or 6, 40320, and 720.
Step-by-step explanation:
We can set each one up as x!, where ! represents factorial and x is the number of guests. This is because the first guest can choose from, say, 4 seats, and then the next guest can choose from 3 seats because one is already taken, and so one.
If your problem wants distinguishable in a way such that the table can be rotated to exclude overcounting, then we have 3!, 8!, and 7!, because for each we can rotate the table around 4, 9, and 8 ways respectively, but still get the same arrangement.
