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noname [10]
2 years ago
6

Find each missing length, will giv brainliest + 50 pts

Mathematics
2 answers:
kipiarov [429]2 years ago
4 0

Step-by-step explanation:

1. 18^2 - 10^2 = 324 - 100 = 224

Sqt(224)=14.9666

Approximate = 14.97

2. 100 - 16 = 84

Sqrt 84 = 9.1652

Approximate = 9.17

3. 225 - 49 = 176

Sqrt 176 = 13.2665

Approximate = 13.27

4. 361 - 144 = 217

Sqrt 217 = 14.7309

Approximate = 14.73

Nina [5.8K]2 years ago
3 0

#1

  • B²=18²-10²
  • B²=324-100
  • B²=224
  • B=14.967(exact)
  • B=14.97(approx)

#2

  • H²=10²-4²
  • H²=100-16
  • H²=84
  • H=9.165(exact)
  • H=9.16(approx)

#3

  • H²=15²+7²
  • H²=225+49
  • H²=274
  • H=16.553(exact)
  • H=16.56(approx)

#4

  • B²=19²-12²
  • B²=361-144
  • B²=217
  • B=15.731(exact)
  • B=15.74(approx)
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In the inequality 6a+4b>10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

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Simplifying:

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3 0
1 year ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

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2 years ago
what is the value of the x variable in the solution to the following system of equations? 2x 2y = 6 x 3y = −1 a. −2 b. 2 c. 5 d.
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2x + 2y = 6 . . . . . (1)
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(1) x 3 => 6x + 6y = 18 . . . . . (3)
(2) x 2 => 2x + 6y = -2 . . . . . (4)

(3) - (4) => 4x = 20
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