Yes! To factor this, you would put it into expanded form: (x+7)(x-7). This is the only way to solve this and eliminate the x^1 term.
3x^2+19x-14=0 Standard form
(3x-2)(x+7)=0 Factored
I don't really know what you're trying to ask because
x = -2 and x=6 are your roots.
But if you want to convert them back to their equation form,
get the other side of the equation to be 0.
x = 6
x - 6 = 0
x = -2
x + 2 = 0
so your original equation had something like (x+2)(x-6)
You have to ask the question with the right type of something.
