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Alchen [17]
1 year ago
7

Help asap (like right now )​

Mathematics
1 answer:
Gemiola [76]1 year ago
4 0

Answer:

B)  Yes, because the slope is -\frac{25}{3} and the zero is (12, 0)

Step-by-step explanation:

From inspection of the graph:

  • y-intercept = (0, 100)
  • Two points:  (3, 75)  and  (6, 50)

\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{50-75}{6-3}=-\dfrac{25}{3}

Therefore, the equation of the line in slope-intercept form y = mx + b

(where m is the slope and b is the y-intercept) is:

y=-\dfrac{25}{3}x+100

To find the zero (when y = 0), set the equation to zero and solve for x:

\implies -\dfrac{25}{3}x+100=0

\implies \dfrac{25}{3}x=100

\implies 25x=300

\implies x=12

Therefore, the zero is at (12, 0)

Therefore, the graph does represent the function because the slope is -\frac{25}{3} and the zero is at (12, 0)

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Please help it’s pretty easy and I’ll reward brainiest
Julli [10]
A, hope this helps!!
8 0
2 years ago
Sin167cos107-cos167sin107
insens350 [35]
Sin 167 = 0.22495

cos 107 = -0.29237

cos 167 = -0.97437

sin 107 = 0.95630

(sin 167)(cos 107) - (cos 167)(sin 107)

(0.22495)(-0.29237) - ( -0.97437)(0.95630)

= 0.86602

hope this helps :)



6 0
2 years ago
What is 2 1/2 /1/3 ?
DanielleElmas [232]

Answer:

15/2

Step-by-step explanation:

My interpretation of your math expression is "2  1/2 divided by 1/3."

I prefer to write this as:

 5        1

----- ÷ -----

 2         3

which is equivalent to:

 5        3

----- * ----- = 15/2

 2        1

5 0
3 years ago
3. Classify each function according to whether it is a vertical stretch, a vertical compression, a horizontal
Vladimir79 [104]

The classifications of the functions are

  • A vertical stretch --- p(x) = 4f(x)
  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

<h3>How to classify each function accordingly?</h3>

The categories of the functions are given as

  • A vertical stretch
  • A vertical compression
  • A horizontal stretch
  • A horizontal compression

The general rules of the above definitions are:

  • A vertical stretch --- g(x) = a f(x) if |a| > 1
  • A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
  • A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
  • A horizontal compression  --- g(x) = f(bx) if |b| > 1

Using the above rules and highlights, we have the classifications of the functions to be

  • A vertical stretch --- p(x) = 4f(x)
  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

Read more about transformation at

brainly.com/question/1548871

#SPJ1

4 0
1 year ago
In which quadrant does O lie if the following statements are true:<br> cos 0 &lt; 0 and cscO &gt; 0
Olin [163]

Answer:

2nd quadrant.

Step-by-step explanation:

\text{Given that,}~ \cos \theta < 0~ \text{and}~ \csc \theta > 0.}\\\\\text{So,}~\cos \theta ~ \text{is negative and}~ \csc \theta ~ \text{is positive.}\\\\\text{In Quadrant II, all other ratios are negative except}~ \sin \theta ~ \text{ and}~ \csc \theta.\\\\\text{Hence, the angle lies in the 2nd quadrant.}~

5 0
1 year ago
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