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Oksanka [162]
3 years ago
6

Which expression is equivalent to (x Superscript one-fourth Baseline y Superscript 16 Baseline) Superscript one-half?

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0

The expression that is equal to (x Superscript one-fourth Baseline y Superscript 16 Baseline) is x Superscript one-eighth Baseline y Superscript 8.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The expression that is equal to (x Superscript one-fourth Baseline y Superscript 16 Baseline) can be found by simplifying the given algebraic equation,

(x^{\frac14}y^{16})^{\frac12}\\\\=x^{(\frac14 \times \frac12)} \times y^{(16 \times \frac12)}\\\\= x^{\frac18}y^{8}

Hence, the expression that is equal to (x Superscript one-fourth Baseline y Superscript 16 Baseline) is x Superscript one-eighth Baseline y Superscript 8.

Learn more about Expression:

brainly.com/question/13947055

#SPJ1

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One factor of the function f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5) Describe how to find the x-intercepts and the y-intercept o
pickupchik [31]

Answer:

x-intercept(s):  (−1.9900717,  0)

y-intercept(s): (0, 52.5)

Step-by-step explanation:

To find the x-intercept, substitute in  0  for  y  and solve for  x. To find the y-intercept, substitute in  0 for x and solve for y .

f(x)=y

(x)=x

<u>x-intercept</u>

To find the x-intercept(s), substitute in  0  for  y  and solve for  x .

f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5

=\bold{0}=x^3-8x^2+17x-10.5\left(x-5\right)

=0\cdot \:10=x^3\cdot \:10-8x^2\cdot \:10+17x\cdot \:10-10.5\left(x-5\right)\cdot \:10

=0=10x^3-80x^2+170x-105\left(x-5\right)

=0=10x^3-80x^2+65x+525

=10x^3-80x^2+65x+525=0

=10x^2-99.90071\dots x+263.80959\dots \approx \:0

\bold{x\approx \:-1.99007\dots}

<u>y-intercept</u>

f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5

=y=\bold{0}^3-8(\bold{0})^2+17(\bold{0})-10.5\left(\bold{0}-5\right)

=y=0-8\cdot \:0+17\left(0\right)-10.5\left(0-5\right)

=y=0-8\cdot \:0+17\cdot \:0-10.5\left(0-5\right)

=y=0-0+0-\left(-52.5\right)

=0-0+0+52.5

\bold{y=52.5}

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