Answer:
13,88,22
On the first evening Jamie received 13 calls.
Step-by-step explanation:
Total number of phone calls received by Jamie over three evenings = 123
Let the number of phone calls received on the third evening = x.
The number of phone calls received on the second evening = 4*x.
The number of phone calls received on the first evening = 
Expressing in equation form:
![\[x+4x+x-9=123\]](https://tex.z-dn.net/?f=%5C%5Bx%2B4x%2Bx-9%3D123%5C%5D)
![\[=>6x-9=123\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E6x-9%3D123%5C%5D)
![\[=>6x=132\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E6x%3D132%5C%5D)
![\[=>x=\frac{132}{6}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%3D%5Cfrac%7B132%7D%7B6%7D%5C%5D)
![\[=>x=22\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%3D22%5C%5D)
So Jamie received 22 calls on the third evening, 88 calls on the second evening and 13 calls on the third evening.
Answer:
4Ф64÷6→β44
Step-by-step explanation:
Answer:
The probability of getting a red jelly bean both of the times is 0.028.
Step-by-step explanation:
First we have that in the box are 12 jelly beans having 2 red and 10 blue. The probability of getting one of the red jelly beans are the sum of the probability of the 2 red jelly beans, that is:

Now we can calculate the probability of getting the red jelly bean twice, this will be the product of the probability of getting each one, is the same probability for the second chance because we are getting the jelly bean back in the box, this is:

Now we have that the probability of getting a red jelly bean both of the times is 0.028.
Answer:
t=−3 or t=−12
Step-by-step explanation:
Step 1: Subtract -36 from both sides.
t2+15t−(−36)=−36−(−36)
t2+15t+36=0
Step 2: Factor left side of equation.
(t+3)(t+12)=0
Step 3: Set factors equal to 0.
t+3=0 or t+12=0
t=−3 or t=−12