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charle [14.2K]
3 years ago
15

Elia rode her bicycle from her house to the beach at a constant speed of 18 kilometers per hour, and then rode from the beach to

the park at a constant speed of 15 kilometers per hour the total duration of the rides was 1 hour and the distances she rode in each direction are equal. Let b be the number of hours it took Elia to ride from her house to the beach, and p the number of hours it took her to ride from the beach to the park
Mathematics
2 answers:
jonny [76]3 years ago
7 0

Answer:

b+p=1 and 18b=15p

Step-by-step explanation:

ASHA 777 [7]3 years ago
5 0

Answer:

Elia was riding \dfrac{5}{11} of an hour from the house to the beach, \dfrac{6}{11} of an hour from the beach to the house and rode

8\dfrac{2}{11} kilometers from the house to the beach and

8\dfrac{2}{11} kilometers from the beach to the house.

Step-by-step explanation:

1. Let b be the number of hours it took Elia to ride from her house to the beach, and p the number of hours it took her to ride from the beach to the park. The total duration of the rides was 1 hour, so

b + p = 1

2. Elia rode her bicycle from her house to the beach at a constant speed of 18 kilometers per hour, she was riding for b hour, then she rode 18b kilometers from her house to the beach.

Elia rode from the beach to the park at a constant speed of 15 kilometers per hour, she was riding for p hours, then she rode 15p kilometers from the beach to the house.

The distances she rode in each direction are equal, so

18b = 15p

3. Solve the system of two equations:

\left\{\begin{array}{l}b+p=1\\ \\18b=15p\end{array}\right.

From the first equation

b=1-p

Substitute it into the second equation

18(1-p)=15p\\ \\18-18p=15p\\ \\18=18p+15p\\ \\33p=18\\ \\p=\dfrac{18}{33}=\dfrac{6}{11}\\ \\b=1-\dfrac{6}{11}=\dfrac{5}{11}

Elia was riding \dfrac{5}{11} of an hour from the house to the beach, \dfrac{6}{11} of an hour from the beach to the house and rode

18\cdot \dfrac{5}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers to the beach and

15\cdot \dfrac{6}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers fro mthe beach to the house.

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