There are 15 boys in school base ball team , they represent 5% of grace Christian school , In all how many are there in school

Please help me Solve for x. Have to show work

REY [17]

A -17 3/4< x so u have to simplify-17 3/4 by multiply 17*4=68+3=71/4 so the x stands for -71/4 and it has to be 4 as the denominator because it it the denominator for the question.
B, C, D are also the same answer-17/4
And for 15 3/4<-2+ x it is also the same answer

6 0

2 years ago

NEED HELP!! PLease!!

nadya68 [22]

For a relation to be called a function, it must pas the vertical line test and each x-value must have a unique y-value

The graph of this sequence would pass the vertical line test.
Each day corresponds to a unique amount of pennies in this sequence.

8 0

2 years ago

Read 2 more answers

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both, in case

lozanna [386]

Answer:

0.3339 = 33.39% probability that both Dave and Mike will show up

Step-by-step explanation:

Probability of independent events:

If A and B are independent events, the probability of both happening at the same time is given by:

$P(A \cap B) = P(A)P(B)$

In this question:

Event A: Dave shows up.

Event B: Mike shows up.

Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.

This means that $P(A) = 1 - 0.47 = 0.53, P(B) = 1 - 0.37 = 0.63$ .

a. What is the probability that both Dave and Mike will show up

$P(A \cap B) = P(A)P(B) = 0.53*0.63 = 0.3339$

0.3339 = 33.39% probability that both Dave and Mike will show up

8 0

2 years ago

The area of a rectangular piece of cardboard is represented by

Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

$A = wl$

w(2w + 3) = 9

From this, we get that:

$l = 2w + 3, A = 9$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question:

$w(2w+3) = 9$

$2w^2 + 3w - 9 = 0$

Thus a quadratic equation with $a = 2, b = 3, c = -9$

Then

$\Delta = 3^2 - 4(2)(-9) = 81$

$w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5$

$w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3$

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

5 0

2 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago