There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate
Look at equation 1,
this can quite easily be manipulated to show
.
Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one
which can then be solved for x since there is only one variable
and then with our x solution we can work out our y solution by using the equation we manipulated
.
So the solution to these equations is x=-2 when y=6
When will they blink together?
what is the smallest number they both mutiply to
3*5=15
so every 15 seconds
so at 15, 30, 45, 60 seconds
so 4 times if you count the time exactly at 1 minute
Answer:
55%
the percent decrease of the sale price from the regular price is 55%
Step-by-step explanation:
Percentage decrease is the percentage change in the sales price (regular and new)
Percentage decrease %∆P = ∆P/Pr × 100%
∆P = change in sales price = $135 - $60.75
Pr = regular price = $135
Substituting the values;
%∆P = (135-60.75)/135 × 100%
%∆P = 55%
the percent decrease of the sale price from the regular price is 55%
Answer: 13
Step-by-step explanation:
65-13=54
54/4=13
Order of operations
We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
