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2 years ago

HELPPP PLEASEEEEE

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

6 0

The second one...maybe, honestly just needed points wait for someone else to anwser

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write a function that has a greater rate of change than one function but a smaller rate of change than the other function

LenaWriter [7]

The function y = 5x has a rate of change that is in between the equation y = 4x and y = 6x.

In an equation, the rate of change is also called the slope. It is the amount that a number is increasing by. We put that value in front of the x in most equations.

In the equal that I gave, the 5 is in between the rates of 4 and 6.

4 0

2 years ago

What is -4+0+y, When y=16

BlackZzzverrR [31]

$\large \mathfrak{Solution : }$

let's plug in the value of y :

-4 + 0 + y

-4 + 16

8 0

2 years ago

Read 2 more answers

Sandy makes $2 profit on every cup of lemonade that she sells and $1 on every cupcake she sells. Sandy wants to sell at least 5

Assoli18 [71]

Answer:

two possible combinations are

- 7 cups of lemonade and 11 cupcakes

- 10 cups of lemonade and 5 cupcakes

Step-by-step explanation:

5 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

2 years ago

julie usd 12 3/4 gallons of water on her garden on monday. she used 15 1/4 gallons of water on tuesday what is th total amount o

sdas [7]

12 3/4 + 15 1/4

12 + 15 = 27
3/4 + 1/4 = 4/4 or the same as 1
27+1=28

So the answer is Julie used 28 gallons of Water.
This problem has my name!!!!!!!!!!!!!

4 0

3 years ago

Read 2 more answers