Answer:
b) One sample z-test for means
Step-by-step explanation:
Normal Distribution
we have μ₀ (population mean from previous studies)
sample size n = 100
standar deviation of population σ = 0.75
And it was determined from sample, that μ = 5 : so we want to know if, at some significance level that value (which is smaller than population mean ) could help in relation to decide about rejecting hypothesis H₀
We should use a z one tail-test for means (left tail)
- f-¹(x) = 69/5y
- f-¹(x) = 13 + 4y/(y + 10)
<h3>How to determine the inverse </h3>
The steps involved in determining the inverse of a function are;
- Replace f(x) with y in the equation describing the function
- Interchange x and y
- Solve for y
- Replace y by f-1(x)
If f(x) = 4/5x + 13
y = 4/5y + 13
y = 4 + 65 /5y
f^-1 = 4 + 65 /5y
f^-1(x)= 69/5y
If f(x)= 3/x+10 + 4
y = 3/y + 10 + 4
y = 3 + 4y + 10/(y + 10)
y = 13 + 4y/(y + 10)
f^-1(x) = 13 + 4y/(y + 10)
Thus, the inverse of the functions is 69/5y and 13 + 4y/(y + 10)
Learn more about functions here:
brainly.com/question/6561461
#SPJ1
Since we already have 3^7 you should know that 3 times 3 is 9. Here is how I would simplify it.
3^7 times 3^4 times 3^3
You should add all the exponents and get
3^14
27 is basically 3 times 3 times 3 which is why I chose to put 27 that way
Hello,
f'(x) = sin(x) - 65 → f(x) = -cos(x) - 65x
Answer:
n[total]=25
n[top finishers]=8
the number of possible outcome
=
outcomes
