Answer:
a) 0.96
b) 0.016
c) 0.018
d) 0.982
e) x = 2
Step-by-step explanation:
We are given with the Probability density function f(x)= 2/x^3 where x > 1.
<em>Firstly we will calculate the general probability that of P(a < X < b) </em>
P(a < X < b) =
=
=
{ Because
}
=
=
=
=
a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }
Comparing with general probability we get,
P(1 < X < 5) =
=
= 0.96 .
b) P(X > 8) = P(8 < X < ∞) = 1/
- 1/∞ = 1/64 - 0 = 0.016
c) P(6 < X < 10) =
=
= 0.018 .
d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)
=
+ (1/
- 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982
e) We have to find x such that P(X < x) = 0.75 ;
⇒ P(1 < X < x) = 0.75
⇒
= 0.75
⇒
= 1 - 0.75 = 0.25
⇒
=
⇒
= 4 ⇒ x =
Therefore, value of x such that P(X < x) = 0.75 is 2.
Answer:
1.5 is not a prime number
Step-by-step explanation:
Answer:
D 6 seconds
Step-by-step explanation:
Hope this helps!!! Please amrk as Brainlyest
Answer:
Value of x using quadratic formula (x = -4) and (x = -5)
Step-by-step explanation:
Given:
Equation
x² + 9x + 20 = 0
Find:
Value of x using quadratic formula
Computation:
Quadratic formula = [-b±√b²-4ac] / 2a
Given equation;
x² + 9x + 20 = 0
a = 1 , b = 9 , c = 20
By putting value
[-9±√9²-4(1)(20)] / 2(1)
[-9±√81-80] / 2
[-9±√1] / 2
(-9 + 1) / 2 , (-9 - 1) / 2
-8 / 2 , 10 / 2
-4 , - 5
Value of x using quadratic formula (x = -4) and (x = -5)
I am not on this yet but i think it is f (x) < 1 < x < 3