Answer:
d= -16
Step-by-step explanation:
To answer this question you'll have to first simplify the equation to
0.2d+-1.2=0.3d+5-3+0.1d
then combining like terms you get
0.2d-1.2=(0.3d+0.1d)+(5+-3)
0.2d-1.2=0.4d+2
then subtract 0.4d from both sides leaving you with
-0.2d-1.2=2
then add 1.2 to both sides
-0.2d=3.2
after you divide both sides by -0.2
leaving you with the answer
D= -16
Yes same thing
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Data for the question :
102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79
Answer:
Range = 25.35
Variance = 29.46
Standard deviation = 5.43
The variation in price of Prozac is high
Step-by-step explanation:
The range of the data :
Maximum - Minimum.
121.2 - 95.35 = 25.35
The variance, s :
s² = Σ(X - m²) / n - 1
Mean, m = Σx / n
X = individual data point
m = mean of data
n = sample size
Using a calculator of save time and ensure accuracy :
s² = 29.45522
The standard deviation, s
s = sqrt(variance)
s = sqrt(s²)
s = sqrt(29.45522)
s = 5.42726.
The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;
With a range of about 25.35 and standard deviation of 5.43
The rate of increase of population of Hermitville is given by:
PR=(Present Population-Past Population)/(Past population)*100
PR=(186480-142340)/142340×100
PR=31.01%
The population increase in Hermitville is 31.01;
This implies that it's population growth is faster than that of Crabville by a factor of
31.01/26=1.19.
The answer is B
