All categories

2 years ago

I need help with my algebra hw

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

5 0

Answer:

well?

Step-by-step explanation:

rosijanka [135]2 years ago

5 0

You have to show the picture

You might be interested in

X − 3 − 2(6 − 2x) = 2(2x − 5)

Finger [1]

Multiply the first bracket by -2

Multiply the second bracket by 2

x-3-12+4x= 4x-10

- negative number times + positive number= - negative number

- negative number times -negative number = + positive number

x+ 4x-3-12= 4x-10

5x-15= 4x-10

Move 4x to the other side

5x-4x-15= 4x-4x-10

x-15= -10

Move -15 to the other side

x-15+15= -10+15

x= 5

Answer : x= 5

7 0

3 years ago

Read 2 more answers

What is the area of circle with a diameter of 22 ft? (use 3.14 for pi; show your work in numbers)

wel

Answer:

69.08

Step-by-step explanation:

π×d

3.14×22=69.08

4 0

2 years ago

Which shows 63 factored into powers of prime numbers? A. 9 • 7 B. 32 • 7 C. 33 • 7 D. 3 • 3 • 7

s2008m [1.1K]

Hi!

<h3>To find the prime factorization of a number, keep dividing by the smallest factor that goes into it. </h3>

63/3 = 21

21/3 = 7

7/7 = 1

<h2>The answer is D. 3 · 3 · 7 </h2>

Hope this helps! :)

-Peredhel

6 0

2 years ago

Read 2 more answers

3. Joe has enough money to purchase up three video games that cost $25 each

zaharov [31]

Answer:

75$ i think lol I did not get the question

5 0

2 years ago

Read 2 more answers

Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t, find

finlep [7]

Answer:

The velocity function is $v(t)=10t+5$ .

The acceleration function is $a(t)=10$ .

When t = 44, the velocity is $v(44)=445 \:\frac{ft}{s}$ .

When t = 44, the acceleration is $a(44)=10\: \frac{ft}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=5t^2+5t$

Velocity is defined as the rate of change of position or the rate of displacement. If you take the derivative of the position function you get the instantaneous velocity function.

$v(t)=\frac{ds}{dt}$

Acceleration is defined as the rate of change of velocity. If you take the derivative of the instantaneous velocity function you get the instantaneous acceleration function.

$a(t)=\frac{dv}{dt}$

The instantaneous velocity function is given by

$v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5$

The instantaneous acceleration function is given by

$a(t)=\frac{dv}{dt} =\frac{d}{dt}(10t+5)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\a(t)=\frac{d}{dt}\left(10t\right)+\frac{d}{dt}\left(5\right)\\\\a(t)=10$

To find the velocity and acceleration when t = 44, we substitute this value into the velocity and acceleration functions

$v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}$

$a(44)=10\: \frac{ft}{s^2}$

6 0

3 years ago