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Rama09 [41]
3 years ago
5

I need help with my algebra hw

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0

Answer:

well?

Step-by-step explanation:

rosijanka [135]3 years ago
5 0
You have to show the picture
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I need help on math plz help fast
lyudmila [28]

Answer:

I believe it is 6.8%

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Step-by-step explanation:

I hope this helps. :)

Feel free to mark brainliest!

6 0
3 years ago
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Quick math problem. Thanks if you help :)
user100 [1]
3 to the power of 9 over 10
4 0
3 years ago
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A circular garden has a circumference of 88 yards. Lars is digging a straight line along a diameter of the garden at a rate of 7
ankoles [38]

Answer:

It will take 4 hours to dig in the garden

Step-by-step explanation:

First we have to calculate the diameter, for this we will use the formula to calculate the circumference of a circle and we will clear the diameter

d = diameter

π = 3.14

c = circumference

c = π * d

d = c / π

d = 88yd / 3.14

d = 28.025yd

round to the nearest whole number

28.025 = 28

d = 28yd

To know how many hours it takes, we divide the diameter by the speed

t = time

v = velocity

t = d / v

t = (28yd) / (7yd/h)

t = 4h

It will take 4 hours to dig in the garden

4 0
3 years ago
Proving the Parallelogram Diagonal Theorem
lora16 [44]

Answer:

The proof is given below.

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE


3 0
3 years ago
Read 2 more answers
A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers"
Maru [420]

Answer:

Answer : D

Step-by-step explanation:

A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is â0.104 to 0.336.  

Which of the following statements is correct?

A) This confidence interval is not reliable because the samples are so small.  

B)This confidence interval is of no use because it contains 0, the value of no difference between classes.  

C)This confidence interval is reasonable because the sample sizes are both at least 5.  

D) This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.

The Answer is D - This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.

In this setup, all the students are already involved in the data. This is not a sample from a larger population, but probably, the population itself.

4 0
3 years ago
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