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1 year ago

9

What is the surface area of the prism in the picture?

2 answers:

ExtremeBDS [4]1 year ago

6 0

Answer:

girl that is so easy, just look it up

nirvana33 [79]1 year ago

5 0

$\bold{ANSWER:}$
390 m^2

$\bold{EXPLANATIONS:}$

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julia-pushkina [17]

The answer is a, i dont think i want the prize tho lol

6 0

2 years ago

Read 2 more answers

The average of 6 numbers is 7. When a 7th number is addedThe average of all numbers is 0. What is the seventh number?

Katena32 [7]

-- The average of 6 numbers is 7.
    So those 6 numbers must add up to 42.

-- If one more number results in an average of zero,
   the new number must be -42 .
   Then all 7 numbers add up to zero.

4 0

3 years ago

Use the properties of exponents to determine the value of aa for the equation:

Phantasy [73]

Answer: a = -2/3

Step-by-step explanation:

Let's start by multiplying both sides by $x$ to simplify:

$4^{1/3} = x^a \times x$

$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x}_{a\ \textrm{times}} \times \,x$

$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x \times x}_{a+1\ \textrm{times}}$

$4^{1/3} = x^{a+1}$

Looking only at the exponents, it seems like $1/3 = a+1$ , so $a = \boxed{-2/3}$ .

5 0

2 years ago

4. An airplane descends at a rate of 1,400 feet per minute. Once the airplane starts its descent, what will be its change in ele

Evgesh-ka [11]

Answer:

5600 feet

Step-by-step explanation:

If it is dropping 1400 every minute then to find the elevation at 4 minutes, you have to multiply 1400 with 4.

5 0

2 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)

Romashka [77]

Answer:

The $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

Step-by-step explanation:

The given function is

$f(t)=-\frac{1}{2}\sin (3t-2\pi)$ .... (1)

The general form of sine function is

$F(t)=A\sin (Bt-C)+D$ ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

$A=-\frac{1}{2}$

$B=3$

$C=2\pi$

$D=0$

So,

$amplitude=|A|=\frac{1}{2}$

$period=3$

$\text{phase shift}=\frac{2\pi}{3}$

Therefore $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

8 0

3 years ago