Answer:
60 cm is the answer
Step-by-step explanation:
Answer:
If he spends $120 dollars a month, and he cut's that down to $50 a month, we should create a pattern to visualize the months.
Step-by-step explanation:
120- 50= 70 ($70 saved each month)
Month 1- $70 saved total
Month 2- $140 saved total
Month 3- $210 saved total
Month 4- $280 saved total
Month 5- $350 saved total
Month 6- $420 saved total
It takes 6 months to get 400 saved. We could also divide to get
5.714285, but it would takes 6 months before reaching the goal. :)
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
-60 -49 -40 9
-45 -18 80 82
-74 -23 14 85
-79 -68 21 46
-48 -21 27 54
-68 -13 4 32
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write
Moreover, we know that the length is 5 meters longer than the width:
We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:
<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
