Equations
Let the number of liters of 80% acid = x
Let the number of liters of 40% acid = y
x + y = 2
80%x + 40%y = 65% * 2
Step One
multiply the 2nd given by 100
(80/100)x + (40/100)y = (65/100)*2
80x + 40y = 2*65 = 130 (3)
Step Two
Multiply the first given equation by 80
80x + 80y = 160 (4)
Step Three
Subtract (4) - (3)
80x + 80y = 160
<u>80x + 40y = 130</u>
40y = 30 Divide by 40
y = 30/40
y = 3/4 = 0.75
What you have found is that out of 2 liters, 0.75 L must be the 40% acid.
Step Four
Find the 80% volume
x + y = 2
y = 0.75 L
x + 0.75 = 2
x = 2 - 0.75
x = 1.25 L
Answers
80% Volume = 1.25 L
40% Volume = 0.75 L
<span>1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
</span>-2x+y=-11<span>
y = 2x-11
</span><span>3x-4y=11
</span>3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
<span>x =33/5
y = 11/5
</span><span>2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
</span><span>(-2x+6y=-12)5
</span>-10x + 30y = -60
<span>(5x-5y=10)2
</span>10x - 10y = 20
Adding the two equations,
<span>-10x + 30y = -60
</span><span>10x - 10y = 20
</span>
20y = -40
y = -2
x = 0
<span>3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
</span><span>-3x-2y=-12
</span>y = -3/2 x + 6
<span>9x+6y=-9
</span>y = -3/2 x - 3/2
Since the slopes are equal then they are parallel lines so they never meet at one point.
Answer:
b= -13
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