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Zolol [24]
2 years ago
7

Write in point slope form an equation of the line that passes through the given point and has the given slope: (0,1); m= 2

Mathematics
1 answer:
sergey [27]2 years ago
3 0

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\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

         Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

<u>Point-slope form</u>:-

      \sf{y-y_1=m(x-x_1)}

Substitute 1 for y₁, 2 for m, and 0 for x₁:-

\sf{y-1=2(x-0)}

So we conclude that Option B is correct.

<h3>Good luck.</h3>

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Look at the circle you created that has point C (the midpoint of AB) as its center and passes through point A. What can you say
Mice21 [21]

The inscribed angle on the circumference of the circle subtended by the diameter at the center is a right angle

What can be said about segment AB is; Segment AB is the diameter of circle with midpoint at C

What can be said about angle BDA is; Angle BDA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BDA is 90°

What can be said about angle BEA is; Angle BEA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BEA is 90°

The given diagram shows;

Circle with midpoint <em>C</em>, along AB, and radius AC

The diameter of circle C = AB

Circle with midpoint <em>A</em>, intersecting with circle <em>C</em> at points <em>D</em> and <em>E</em>

Tangents from point B on circle, <em>C</em>, intersect with circle <em>A</em> at points <em>D</em> and <em>E</em>

<em> </em>

Required parameters;

  • What can be said about AB

The segment AB is a line that intersects the circle <em>C</em> at two points and also passes through the the point <em>C</em> which is the center of the circle <em>C</em>

Therefore, the segment AB is the diameter of the circle with center at <em>C</em>

  • What can be said about angle BDA

The angle BDA is the inscribed angle of circle <em>C</em> subtended by the points <em>A</em> and <em>B</em> which specifies the diameter of the circle with midpoint <em>C</em>

Therefore, the angle BDA is subtended by the diameter of the circle at the center

According to circle theorem, we have;

Angle subtended at the center = 2 × The angle subtended at the circumference

The angle subtended at the center by the diameter AB = 180° (Angle on a straight line)

Therefore;

The angle subtended at the center = 180° = 2 × Angle BDA

Angle BDA = 180°/2 = 90°

Angle BDA  = 90°

  • What can be said about angle BEA

Similarly, we have;

The angle subtended at the center = 180° = 2 × Angle BEA

Angle BEA = 180°/2 = 90°

Angle BEA = 90°

Find out more about inscribed angles of a circle here:

brainly.com/question/17021375

7 0
3 years ago
Can somebody help me solve this?
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Answer:

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sin 76°/z = sin 51°/2.6

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z·(sin 51°) = 2.6·(sin 76°)

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Answer:
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7 0
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Please help me I don’t understand this
Lyrx [107]
When you're given a point and the slope of a line, it is often easiest to write its equation in point-slope form.

This is y-y_1=m(x-x_1), where (x_1,y_1) is the ordered pair for the point you are given and m is the slope.

Here, you would write y-8=-3(x-7). Then, you simplify to get to slope-intercept form, which is y = mx+b, where b is the y-intercept.

y-8=-3(x-7) \\ y=-3x+29

The correct answer is A.
6 0
3 years ago
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