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shtirl [24]
3 years ago
9

You have taken over an abandoned drilling project. After drilling for 2 hours, the depth is 110 feet. After 5 hours, the depth h

as increased to 114.5 feet. Write an equation in the form y = mx + b to describe the relationship between x, the hours of drilling, and y, the depth of the well.
Mathematics
1 answer:
seraphim [82]3 years ago
5 0
(2,110)(5,114.5)
slope = (114.5 - 110) / (5 - 2) = 4.5 / 3 = 1.5

y = mx + b
slope(m) = 1.5
use either of ur points..(2,110)...x = 2 and y = 110
now we sub and find b, the y int
110 = 1.5(2) + b
110 = 3 + b
110 - 3 = b
107 = b

so ur equation is : y = 1.5x + 107 <==
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Which of the following expressions is NOT equivalent to (x − 6)(x − 3)?
kodGreya [7K]

Answer:

B. x(x) + (−6)(−3)

NOT equivalent  to (x − 6)(x − 3)

Step-by-step explanation:

(x − 6)(x − 3)

= x^2 - 3x - 6x + 18

= x^2 - 9x + 18

A. (6 − x)(3 − x)

= 18 - 6x - 3x + x^2

= 18 - 9x + x^2

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

B. x(x) + (−6)(−3)  = x^2 + 18   ----> NOT equivalent  to (x − 6)(x − 3)

C. x2 − 3x − 6x + 18   = x^2 - 9x + 18  --> equivalent  to (x − 6)(x − 3)

D. x(x − 6) − 3(x − 6)

= x^2 - 6x - 3x + 18

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

4 0
3 years ago
Find the X COORDINATE OF THE intersection of 9x - 6y = 12 and 3x + 2y =8
yaroslaw [1]

Answer: x=2

Step-by-step explanation:

Given a System of linear equations, the solution of the system is the point (x,y) in which the lines intersect, where "x" is the x-coordinate and "y" is the y-coordinate.

Having the following System of equations:

\left \{ {{9x - 6y = 12} \atop {3x + 2y =8}} \right.

You can use the Elimination method to find the value of "x":

-Multiply the second equation by 3.

- Add the equations.

- Solve for "x".

Then, you get:

\left \{ {{9x - 6y = 12} \atop {9x +6y =24}} \right.\\.......................\\18x=36\\\\x=\frac{36}{18}\\\\x=2

8 0
3 years ago
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goblinko [34]

Answer:

8x^{3}-34x^{2}+25x-3

Step-by-step explanation:

In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):

(4x-3)(2x^{2}-7x+1)

(4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)

8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)\\

8x^{3}-28x^{2}+4x-6x^{2}+21x-3

Let's combine like terms to get our final answer:

8x^{3}-28x^{2}-6x^{2}+4x+21x-3

8x^{3}-34x^{2}+25x-3

6 0
3 years ago
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alukav5142 [94]

Answer:

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Step-by-step explanation:

3 0
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Answer:

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Step-by-step explanation:

7 0
2 years ago
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