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-Dominant- [34]
2 years ago
5

In 2006, 95% of new cars in the US came with a spare tire. In 2017, 72% came with a spare tire.

Mathematics
1 answer:
MArishka [77]2 years ago
7 0

Using the Central Limit Theorem, it is found that:

  • The mean is 0.23.
  • The standard deviation is s = \sqrt{\frac{0.95(0.05)}{250} + \frac{0.72(0.28)}{250}}.

<h3>Central Limit Theorem</h3>
  • It states that for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportions has mean p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}
  • When two variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In 2006, 95% of new cars in the US came with a spare tire, with a sample of 250, hence:

p_1 = 0.95, s_1 = \sqrt{\frac{0.95(0.05)}{250}}

In 2017, 72% of new cars in the US came with a spare tire, with a sample of 250, hence:

p_2 = 0.72, s_2 = \sqrt{\frac{0.72(0.28)}{250}}

Hence, for the distribution of differences:

p = p_1 - p_2 = 0.95 - 0.72 = 0.23

s = \sqrt{s_1^2 + s_2^2} = \sqrt{\frac{0.95(0.05)}{250} + \frac{0.72(0.28)}{250}}

To learn more about the Central Limit Theorem, you can take a look at brainly.com/question/16695444

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Find the circumference and the area of a circle with diameter 7 cm.
Ilia_Sergeevich [38]

Answer:

21.98 is the circumference because is it 7 pi 7 times 3.14. For the area though it is 38.48 because you need to get the radius of the circle and you divided 7 by 2 which is 3.5 and here is the work A=πr2=π·3.52≈38.48451

Step-by-step explanation:

Hope this helped and you understood if you want it would help a lot if you put it brainliest.

3 0
3 years ago
An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

D4 = 192 + 3.14 * (48 + 15) = 389.82 yd

D5 = 192 + 3.14 * (48 + 20) = 405.52 yd

D6 = 192 + 3.14 * (48 + 25) = 421.22 yd

D7 = 192 + 3.14 * (48 + 30) = 436.92 yd

D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

6 0
3 years ago
1. Simplify. (343)1/3
elena-s [515]

1) 343/32 or 10.71875 or 10 23/32
2)-8
3)7
8 0
3 years ago
For the functions f(x) = x^2+ 8x + 2 and g(x) = -5+9, find (f•g)(x)and (f.g)(-1).
Ne4ueva [31]

Answer:  (f·g)(x) = -5x³ - 31x² + 62x + 18

               (f·g)(-1) = -70

(fog)(x) = 25x² - 130x + 155

(fog)(-1) = 310

<u>Step-by-step explanation:</u>

f(x) = x² + 8x + 2          g(x) = -5x + 9

(f·g)(x) = (x² + 8x + 2)(-5x + 9)

          = -5x³ + 9x²

                    - 40x² + 72x

            <u>                    - 10x + 18</u>

          = -5x³ - 31x² + 62x + 18

(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18

         =  -5(-1)  - 31(1)    - 62      + 18

         =    5     -   31      - 62      + 18

         =  -70

****************************************************************************************

(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2

           = 25x² - 90x + 81

                       - 40x + 72

              <u>                   +   2</u>

           = 25x² - 130x + 155

(fog)(-1) = 25(-1)² - 130(-1) + 155

            =   25    +  130    + 155

            = 310

<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>

6 0
3 years ago
The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon
iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0
3 years ago
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