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Nikitich [7]
3 years ago
14

PLSSSS HELP Find the intersection of the circle x^2+ y^2 = 29 and y = x - 3 algebraically,

Mathematics
1 answer:
Marina86 [1]3 years ago
6 0
Uhhh what grade u in?!?
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(57 – 42) X-3 – 21<br><br> Help me out please
SpyIntel [72]

Answer:

1065

Step-by-step explanation:

57-42×-3-21

7 0
4 years ago
Simplify (-5)^5 over (-5)^-6
xxMikexx [17]

Answer:

− 48828125

Step-by-step explanation:

you can use a calculator for algebra

5 0
3 years ago
Someone please help me out with these questions . I don’t get them at all.
iVinArrow [24]

Answer:

a)similar; b)similar; c)similar; d)NOT similar

Step-by-step explanation:

>In general if

all corresponding angels are ≅, and

all corresponding sides are in proportion

then the Δs are similar

>we have 3 similarity theorems AA, SSS, and SAS

a)

we can use that sum of angles in a triangle is 180 to find the missing angles

180-96-32 = 52

so in the smaller triangle the angles are 96°-52°-32°

in the larger triangle the angles given are 52°-32°

Since there are 2 corresponding angles congruent, AA theorem of similarity says that the 2 triangles are similar. The transformations were that the big triangle was shrunk and rotated

b)

here we are given a pair of congruent angles and we need to check if the sides are in proportion, is 14/44.8 equal to 20/64?

14/44.8 =.3125 is equal to 20/64=.3125

since we have two corresponding sides in proportion and the angles in between them congruent the SAS theorem says that the 2 triangles are similar. The transformation was that the small triangle was dilated.

c)

because we are given the 2 angles are congruent we can conclude that the lines NH and SL are parallel. NH║SL let us conclude that ∡H and ∡ L are congruent because 2 parallel lines cut by a transversal (ML in our case) form congruent angles. So ΔMNH  is similar to ΔMSL because of AA theorem of similarity (one pair of A was given congruent, one other pair of A we concluded was congruent)

d)

here we have to check if all the sides are in proportion to see if SSS theorem of similarity applies here

18/90 = .2

44/202.4≈.22

58.5/211.2≈.28

.2≠ .22 ≠ .28

since the sides are not in proportion the 2 triangles are NOT similar.

4 0
3 years ago
15 points PLEASE ANSWER
Xelga [282]

Answer:

D. (25π - 50) sq m

Step-by-step explanation:

Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.

I hope this helped! :D

4 0
3 years ago
[final due to glitching] find the value of x for this parallelogram
Butoxors [25]

Answer:

x = 0

Step-by-step explanation:

both angles equal each other

I hope this helps

5 0
2 years ago
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