<span>49.97%
For this problem, let's consider the probability of each of the four possibilities for having two children, being BB, BG, GB, and GG. Then sum the probabilities for both the BG and GB events. So
BB = 51.3% * 51.3% = 26.3169%
BG = 51.3% * 48.7% = 24.9831%
GB = 48.7% * 51.3% = 24.9831%
GG = 48.7% * 48.7% = 23.7169%
If you check, you'll notice that the sum of all the probabilities add up to 100% like it should. And the sum of BG + GB is
24.9831% + 24.9831% = 49.9662%
which when rounded to 2 decimal places is 49.97%</span>
Answer:
75% of getting a normal child next
Explanation:
If you plug in the traits of two normal adults into a Punnett Square you will get a ratio of 1:4 or 25% chance of getting an albino child (Example: AA, Aa, Aa, aa) "A" representing the dominant trait, and "a" representing the recessive trait.
B! I hope this is correct!
Options are not provided in teh question. The complete question is as following:
Which of the following classes of antibodies is most likely to be made by the oldest plasma cell in a population of B cells?
a. IgM
b. IgG
c. IgA
d. None of the listed responses is correct.
Answer:
c. IgA
Explanation:
Specialized white blood cells called B lymphocytes (or B cells) contain antibodies. The mature B cells, or plasma cells, secrete millions of antibodies into the lymphatic system and the bloodstream. The plasma cell antibodies have the exact same antigen-binding site and specificity as the precursors to their B cells. Five different types of antibodies are present in humans: IgA, IgM, IgG, IgD,IgE.
In the oldest plasma cell igA classes of antobodies are present because initially plasma cells secret IgM but it switch and forms IgG, as the plasm aget older ans switch of antibodies takes place for scond time they can make IgA or IgE.
Hence, the correct option is c. IgA.
right answer is "False"\
because every tRNA has its specific amino acid