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1 year ago

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Team with an exame The radius of a circle is 7 kilometers. What is the length of a 45° arc?

1 answer:

Igoryamba1 year ago

6 0

Answer:

Step-by-step explanation:

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A homeowner listed her real estate for sale at $100,000. If her cost was 80% of the listing price, what will her percentage of p

sammy [17]

Answer:

25%

Step-by-step explanation:

Her profit is $20,000 on her cost of $80,000, so is ...

20,000/80,000 × 100% = 25%

7 0

2 years ago

What is the area of a rectangles with the side lengths 5 inches and 1/3 inches?

sveticcg [70]

Answer:

area of a rectangle is length multiplied by breath, which is the multiplication of 5 an 1/3

3 0

2 years ago

Which ordered pairs are solutions to the inequality 3x-4y>5

Sloan [31]

Note: you did not provide the answer options, so I am, in general, solving this query to solve your concept, which anyways would clear your concept.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

$3x-4y>5$

All we need is to find any random value of 'x' and then solve the inequality.

For example, putting x=3

$3\left(3\right)-4y>5$

$9-4y>5$

$-4y>-4$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

$\left(-4y\right)\left(-1\right)$

$4y$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4y}{4}$

$y$

So, at x = 3, the calculation shows that the value of y must be less

than 1 i.e. y<1 in order to be the solution.

Let us take the random y value that is less than 1.

As y=0.9 < 1

so putting y=0.9 in the inequality

$3\left(3\right)-4\left(0.9\right)$

$=9-3.6$

$=5.4$

As 5.4 > 5

Means at x=3, and y=0.9, the inequality is satisfied.

Thus, (3, 0.9) is one of the many ordered pairs solutions to the inequality 3x-4y>5.

6 0

2 years ago

Colby and Sarah sold newspapers this past summer. Colby earned $4.50 for each newspaper he sold. Sarah's earnings were $35 less

Furkat [3]

Y represent the total number of newspapers sold by Colby.

5 0

2 years ago

Read 2 more answers

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

2 years ago