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Marrrta [24]
3 years ago
5

Car crash teste are typically done at 35 mph, which is approximately 15.6 m/s. A car has a mass of 1,600kg. Calculate the moment

um of this car.
Physics
1 answer:
shutvik [7]3 years ago
8 0

This question involves the concepts of momentum, speed, and mass.

The momentum of the car is "24960 N.s".

<h3>MOMENTUM</h3>

Momentum is defined as the quantity of motion contained in a body. Mathematically, it is defined as the product of the mass and speed of the object:

P = mv

where,

  • P = momentum = ?
  • m = mass = 1600 kg
  • v = speed = 15.6 m/s

Therefore,

P = (1600 kg)(15.6 m/s)

P = 24960 N.s

Learn more about momentum here:

brainly.com/question/904448

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Momentum is transferred through the convert wich in this case is the golf club
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4 years ago
How would i solve these problems, nobody in my class understands and there is a substitute
DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is 0.87 m/s^2

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

  • Horizontal component: F_x = (765)(cos 42.0^{\circ})=568.5 N
  • Vertical component: F_y = (765)(sin 42.0^{\circ})=511.9 N

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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3 years ago
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Answer:

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However, due to the large mass of the Earth, compared to the mass of the Hulk, the downward motion of the Earth due to the reaction force (equal to the force with which the Hulk leaps) is negligibly small, such that the Earth can absorb the Hulk's leap force by reacting mainly locally, at the leap point  by forming a crater, while the Earth in general, remains in the same place

Explanation:

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