Question

How would i solve these problems, nobody in my class understands and there is a substitute

Answer 1

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is $0.87 m/s^2$

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

$F_x = F cos \theta\\F_y = F sin \theta$

where

F = 765 N is the magnitude of the force

$\theta=42.0^{\circ}$ is the angle of the force with the horizontal

Substituting, we find:

• Horizontal component: $F_x = (765)(cos 42.0^{\circ})=568.5 N$
• Vertical component: $F_y = (765)(sin 42.0^{\circ})=511.9 N$

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

$F_x = F cos \theta$

where

F = 100 N is the magnitude of the pulling force

$\theta=30.0^{\circ}$ is the direction of the force with the horizontal

Substituting,

$F_x = (100)(cos 30^{\circ})=86.6 N$

Now we can find the acceleration of the wagon by using Newton's second law:

$F_x = ma_x$

where

$F_x = 86.6 N$ is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

$a_x$ is the acceleration in the horizontal direction

Solving for $a_x$, we find

$a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2$

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

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