A vase of flowers is stationary on a table. which of the following statements best explains why the vase is stationary?

A container has a 5m^3 volume capacity and weights 1500 N when empty and 47,000 N when filled with a liquid. What is the mass de

Helen [10]

Answer:

927.62 kg/m³ and 0.9275.

Explanation:

Density: This can be defined as the ratio of the mass of a body and its volume.

The S.I unit of density is kg/m³.

Mathematically, Density can be expressed as

D = m/v......................... Equation 1

Where D = density of the body, m = mass of the body,v = volume of the body

Also,

m = W/g.................... Equation 2

Where W = weight of the body, g = acceleration due to gravity.

Given: W = 47000 - 1500 = 45500 N, g = 9.81 m/s²

Substitute into equation 2,

m = 45500/9.81

m = 4638.12 kg.

Also given: v = 5 m³

Substitute into equation 1,

D = 4638.12/5

D = 927.62 kg/m³

Hence the mass density of the liquid = 927.62 kg/m³

Specific gravity: This is the ratio of the density of a body to the density pf water.

R.d = D/D'................................ Equation 3

Where R.d = specific gravity, D = density of the liquid, D' = density of water.

Given: D = 927.62 kg/m³, D' = 1000 kg/m³

Substitute into equation 3

R.d = 927.52/1000

R.d = 0.9275.

Hence the specific gravity of the liquid = 0.9275.

6 0

3 years ago

A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direct

Andreyy89

The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

<h3>Magnitude of magnetic force on the proton</h3>

The magnitude of magnitude force on the proton is calculated as follows;

F = qvB sinθ

where;

q is the charge of the proton
v is the speed of the proton
B is the magnitude of the magnetic filed
θ is the angle between the field and speed

Substitute the given parameters and solve for the magnetic force.

F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)

F = 2.4 x 10⁻¹² N

Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Learn more about magnetic force here: brainly.com/question/13277365

7 0

3 years ago

Commercially-available hybrid vehicles, such as the Toyota Prius, use electrical batteries to store energy for later use. Howeve

Bad White [126]

(A) $4.2\cdot 10^5 J$

The energy stored by the system is given by

$E=Pt$

where

P is the power provided

t is the time elapsed

In this case, we have

P = 60 kW = 60,000 W is the power

t = 7 is the time

Therefore, the energy stored by the system is

$E=(60,000 W)(7 s)=4.2\cdot 10^5 J$

(B) 4830 rad/s

The rotational energy of the wheel is given by

$E=\frac{1}{2}I \omega^2$ (1)

where

$I$ is the moment of inertia

$\omega$ is the angular velocity

The moment of inertia of the wheel is

$I=\frac{1}{2}MR^2=\frac{1}{2}(5 kg)(0.12 m)^2=0.036 kg m^2$

where M is the mass and R the radius of the wheel.

We also know that the energy provided is

$E=4.2\cdot 10^5 J$

So we can rearrange eq.(1) to find the angular velocity:

$\omega=\sqrt{\frac{2E}{I}}=\sqrt{\frac{2(4.2\cdot 10^5 J)}{0.036 kg m^2}}=4830 rad/s$

(C) $2.8\cdot 10^6 m/s^2$

The centripetal acceleration of a point on the edge is given by

$a=\omega^2 R$

where

$\omega=4830 rad/s$ is the angular velocity

R = 0.12 m is the radius of the wheel

Substituting, we find

$a=(4830 rad/s)^2 (0.12 m)=2.8\cdot 10^6 m/s^2$

7 0

4 years ago

Consider a resonator with ω0 = 100 rad/sec and a Q factor of 100. Calculate the time takes it to settle within 2% of the final v

Alla [95]

Answer:

8 s

Explanation:

Damping factor, F is given by

$F=\frac {1}{2Q}$ where Q is quality factor

Also, we know that the settling time, T is given by

$T=\frac {4}{FW}$ where W is the resonant frequency.and substituting the first equation here we get

$T= \frac {4\times 2Q}{W}$

Since it takes 2% of final value to settle and considering 100 rad/s for resonant frequency and taking quality factor of 100 then

$T=\frac {4\times 2\times 100}{100}= 8 s$

5 0

3 years ago

A particle is confined between rigid walls separated by a distance L = 0.167 nm. The particle is in the second excited state (n

ZanzabumX [31]

Answer:

The answer for a classical particle is 0.00595

Explanation:

The equation of the wave function of a particle in a box in the second excited state equals:

ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)

The probability is equal to:

P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx

for x = 0.166 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3

for x = 0.028 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3

for x = 0.067 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3

therefore, the classical probability is equal to:

(1/L)dx = (1/0.167)*100 pm = 0.00595

8 0

3 years ago