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3 years ago

6

Equation perpendicular to y=-2x+5 and goes through point (-3,4)

1 answer:

rusak2 [61]3 years ago

7 0

Answer:

y = $\frac{1}{2}$ x + $\frac{11}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 5 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$ , thus

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - $\frac{3}{2}$ + c ⇒ c = 4 + $\frac{3}{2}$ = $\frac{11}{2}$

y = $\frac{1}{2}$ x + $\frac{11}{2}$ ← equation of perpendicular line

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Ainat [17]

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3 years ago

One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

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VladimirAG [237]

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