Answer:
<h2>
x₁ = - 2 + √2 , x₂ = - 2 - √2</h2>
Step-by-step explanation:

Answer:
300 times
Step-by-step explanation:
600 * 1/2 = 600/2
=300
Answer: The third answer Y = 2X + 3
Answer:

Step-by-step explanation:
This half life exponential decay equation goes by the formula:

Where

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:
So,

Now

third choice is correct.
Mrs. Benson has 184 math assignments left to grade.
<u>Step-by-step explanation:</u>
Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:
Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , Assignments left to grade is :
⇒ 
⇒ 
Therefore , Mrs. Benson has 184 math assignments left to grade.