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Afina-wow [57]
2 years ago
8

How do you graph y=x^2-2x-3

Mathematics
1 answer:
lara [203]2 years ago
3 0

The graph of the given quadratic equation will be along the y-axis and cuts the intercepts at x (-1,3) points.

<h3>What is a graph? </h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

The given quadratic equation is:-

y  =  x² - 2x - 3

So the value of x will be (-1,3) so the quadratic curve will cut the intercepts at x(-1,3).  The graph of the quadratic equation is attached with an answer.

To know more about graphs follow

brainly.com/question/25020119

#SPJ1

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Is 2 pounds of meat will serve 5 people, how many pounds will be needed to serve 13 people?
Rina8888 [55]

Answer:

6 pounds

Step-by-step explanation:

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3 years ago
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Find an equation for the ellipse that satisfies the given conditions.
svetoff [14.1K]

Answer: (x^2)/25 + (16y^2)/375) = 1

Step-by-step explanation:

since foci are symetrically located on x-axis about origin, the equation of the ellipse must be of the following form:

  (x^2)/(a^2) + (y^2)/(b^2) = 1, where a = semi-major axis, and b = semi-minor axis,

and:  e = eccentricity = sqrt(a^2 - b^2)/a = 0.25;  foci located at (+/- sqrt(a^2 - b^2),0) = (+/- 1.25,0)

---> sqrt(a^2 - b^2) = 1.25 ---> 1.25/a = 0.25 ---> a = 1.25/0.25  ---> a = 5; and sqrt(a^2 - b^2) = 1.25 = 5/4

---> a^2 - b^2 = (5/4)^2 = 25/16;  or 5^2 - b^2 = 25/16 ---> 25 - b^2 = 25/16;  

---> b^2 = 25 - (25/16) = 25[1 - 1/16] = 25(15)/16 = 375/16

---> (x^2)/25 + (y^2)/(375/16) = 1 ---> (x^2)/25 + (16y^2)/375) = 1

Hope this help...and correct it's been awhile..Let me know

4 0
3 years ago
A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich
Bess [88]

Answer:

a). k = 2.0794

b). A_{t}=A_{0}(2^{3t} )

c). 13107200 cells

d). rate of growth after 6 hours = 27255112

e). 4.76 hours

Step-by-step explanation:

From the formula of bacterial population,

A_{t}=A_{0}e^{kt}

Where A_{t} = Bacterial population after time t

A_{0} = Initial population

k = relative growth factor

t = duration or time

a). For A_{t}=2\times 50=100 cells

and A_{0}=50 cells

Time t = 20 minutes = \frac{1}{3} hours

Now we plug in these values in the formula,

100 = 50(e^{\frac{k}{3}})

e^{\frac{k}{3}}=2

By taking natural log on both the sides of the equation,

\frac{k}{3}(lne)=ln(2)

k = 3ln(2) = 2.0794

b). To get the expression we will plug in the value of k in the formula.

A_{t}=A_{0}e^{kt}

Since k = 3ln(2)

A_{t}=A_{0}e^{3t(ln2)}

Let y = e^{3t(ln2)}

By taking natural log on both the sides of the equation,

lny = ln(e^{3t(ln2)} )

lny = 3t(ln2)ln(e)

ln(y) = 3t(ln2)

ln(y) = ln(2)^{3t}

y = 2^{3t}

Now our expression will be A_{t}=A_{0}(2^{3t} )

c). Number of cells after t = 6 hours

A_{6}=50(2^{3\times 6} )

A_{6}=50(2^{18})

A_{6}=50\times (262144)=13107200

d). We can get the rate of growth by finding derivative of the expression

\frac{d}{dt}(A_{t})=\frac{d}{dt}[A_{0}(e^{kt}})]

          = A_{0}[ke^{kt}]

Now \frac{d}{dt}(A_{6})=k.A_{6}

                   = 2.0794×13107200

                   = 27255112

e) From the given formula,

A_{t}=A_{0}(2^{3t} )

1000000=50(2^{3t} )

2^{3t}=20000

3t(ln2) = ln(20000)

t = \frac{ln(20000)}{3(ln2)}

t = \frac{9.90349}{2.07944}=4.76 hours

3 0
3 years ago
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Svetach [21]

Please mark me the braniliest

Answer:

Radius = 12in

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Height = 30in

Step-by-step explanation:

Trust me I took the test

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mr Goodwill [35]

Answer:

x = 35°

Step-by-step explanation:

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Solve for x. Subtract 145 from both sides:

x+145-145=180-145\\\\x=35

The value of x is 35°.

:Done

8 0
3 years ago
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