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2 years ago

10

Need help! will award brainiest

2 answers:

alexdok [17]2 years ago

8 0

Answer: -1/3

Step-by-step explanation:

The equation to find the slope of a line is $\frac{y2 - y1}{x2-x1}$ . Y1 is 5, Y2 is 3, X1 is 2, and X2 is -4. Plug these numbers in to get the equation $\frac{5-3}{(-4)-2}$ . 5-3 = 2. (-4)-2 = -6. This gives a slope of 2/-6, which can be reduced by dividing the numerator and denominator by 2 to get a final slope of -1/3.

coldgirl [10]2 years ago

4 0

Answer:

$\sf slope: \boxed{\bf \frac{1}{3} }$

Explanation:

$\sf slope :\dfrac{y_2-y_1}{x_2-x_1} =\dfrac{rise}{run} \ \ \ \ where \ (x_1, \ y_1) ,(x_2, \ y_2) \ are \ points$

Find slope:

$\rightarrow \sf \dfrac{x_2-x_1}{y_2-y_1}$

<em>insert values</em>

$\rightarrow \sf \dfrac{3-5}{-4-2}$

<em>simplify</em>

$\rightarrow \sf \dfrac{1}{3}$

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vampirchik [111]

Answer:

7

Step-by-step explanation:

You can convert the fourth square roots to $7^{\frac{1}{4}}} * 7^{\frac{1}{4}}} * 7^{\frac{1}{4}}} * 7^{\frac{1}{4}}}$ . Using the product of powers rule, we can add the four terms' exponents, resulting in $7^1$ , which is 7.

8 0

3 years ago

Oh freight elevator can hold a maximum weight of 3500 pounds and delivery man weighs 200 pounds is delivering curtains that each

mario62 [17]

Answer:

$200+48n\leq 3500$

$n\leq 66.7$

Step-by-step explanation:

The freight elevator can hold a maximum weight of 3500 pounds
The delivery man weighs 200 pounds
Each carton weighs 48 pounds

Let the number of cartons he can safely put on the elevator at one time=n

Total weight of Carton=48n

Since the weight of the man and the cartons combined must not be more than 3500 pounds,

Therefore,an inequality that represents the situation is:

$200+48n\leq 3500$

We can solve for n if required

$200-200+48n\leq 3500-200\\48n\leq 3200\\\text{Divide both sides by 48}\\n\leq66.7$

The delivery man can safely carry 66 Cartons.

4 0

3 years ago

Express as a trinomial<br> (3x + 4)(3x – 10)

Oliga [24]

9x
2
−18x−40
9x square minus 18x minus 40

4 0

3 years ago

How can you solve 30×20 using compatible numbers

Olin [163]

You could go 3×10 × 10×2

5 0

4 years ago

Oint C is on line segment BD‾\overline{BD} BD . Given BD=5x,BD=5x, BD=5x, BC=4x,BC=4x, BC=4x, and CD=4,CD=4, CD=4, determine the

Gennadij [26K]

Answer:

Therefore the required value of $\overline{BD}$ is 20 units.

Step-by-step explanation:

Line Segment: Line segment is a portion of a line whose has two end points.

Given that point C is on the line segment $\overline{BD}$ .

$\overline{BD}$ = 5x , $\overline{BC}$ = 4x and $\overline{CD}$ = 4

C is the point of the line segment of $\overline{BD}$ .

So we can write

$\overline {BD}= \overline{BC}+\overline{CD}$

Putting the values of $\overline{BD}$ , $\overline{BC}$ and $\overline{CD}$

5x=4x+ 4

⇒5x-4x= 4

⇒x=4

So we get the value of x.

To get the value of $\overline{BD}$ , we need to put the value of x in the value of $\overline{BD}$ .

Therefore,

$\overline{BD}$ = 5×4

=20

Therefore the required value of $\overline{BD}$ is 20 units.

3 0

3 years ago