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Crazy boy [7]
3 years ago
12

Joni bought 35 books at a price of Rp. 122,500. Toni bought the same 24 books as

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

Toni pays 84000

Step-by-step explanation:

Data :

Joni books = 35

Joni price = 122500

Toni books = 24

Find price of single book

      122500/35 =  3500

Toni prices if 24 books is

    24 × 3500 =  84000

You might be interested in
25. What is the range of the list of numbers 3,22, 16, 8, 34, 7, and 20?
antoniya [11.8K]

Answer:

31

Step-by-step explanation:

The range of a set of data is the difference between the highest and lowest values in the set.

First arrange all the figures in order from the smallest to the largest value

3,7,8,16,20,22,34

Therefore, finding range would be; 34-3 =31

Hope this helps!

7 0
3 years ago
How to factorise 7x+7 and x²+2x i need help bad
jasenka [17]
There is a 7 in both 7x and 7 so you will take that out.

7 (x+1)

Then there is an x in both x2 and 2x so you take that out.

x (x+2)
6 0
3 years ago
If b√2 = 6, what does b equal? I don't know why I'm stuck on this problem, but could somebody help me?
kotegsom [21]

Answer:

Step-by-step explanation:

Divide both sides by the square root of 2. If you are looking for an exact answer that is rationalized, it would be found by multiplying 6/sqrt(2) * sqrt(2)/sqrt(2) to get

b=\frac{6\sqrt{2} }{2}=3\sqrt{2}

8 0
3 years ago
Read 2 more answers
NEED AN EXPERT PLZ ASAP
Grace [21]
System of equations:
x + y = 23
x - y = 7           

Add them together
2x = 30
x = 15

Now plug 15 into one of the equations:
15 + y = 23
y = 8

your two numbers are 15 and 8
5 0
4 years ago
Read 2 more answers
Find the value of unknown figure plz tell i will mark as brainliest
NeTakaya

Answer:

1. 2^{3} x 3^{6}

ii. 18

b. -12

2. nth = a + (n - 1)d

ii. k = 103

3. x^{o} = 27^{o}

4. Volume = 25.025 m^{3}

Step-by-step explanation:

1. Prime factors of 5832 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3

                                       = 2^{3} x 3^{6}

ii. \sqrt[3]{5832} = 18

b. 2a^{2} - 3b^{2} + 3abc

a = 3, b = 2, c = -1

Thus,

2(3)^{2} - 3(2)^{2} + 3(3 x 2 x -1)

= 18 - 12 - 18

= -12

2. The required formula is;

nth = a + (n - 1)d

where: a is the first term, n is the number of terms in the sequence and d is the common difference.

b. kth term = 304, then

304 = -2 + (k - 1) 3

      = -2 + 3k -3

      = 3k - 5

3k = 304 + 5

3k =  309

k = \frac{309}{3}

  = 103

k = 103

3. Comparing <DAB and < EBC;

<DAB ≅ <EBC = x^{o}

<BEC = 90^{o} (right angle property)

<C = 63^{o}

Thus,

<B + <C + <E = 180^{o} (sum of angles in a triangle)

x^{o} + 63^{o} + 90^{o} = 180^{o}

x^{o} + 153 = 180^{o}

x^{o} = 180 - 153

   = 27

x^{o} = 27^{o}

4. Volume of a cylinder = \pir^{2}h

where r is the radius and h is the height of the cylinder.

Diameter = 3.5 m, h = 2.6 m

r = \frac{3.5}{2}

r = \frac{7}{4} m

So that,

Volume = \frac{22}{7} x (\frac{7}{4}) ^{2} x 2.6

             = \frac{22}{7} x \frac{49}{16} x \frac{13}{5}

             = 25\frac{1}{40}

Volume = 25.025 m^{3}

6 0
3 years ago
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