<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
Answer:

(f-g)(-4) = -151
Step-by-step explanation:
To find f-g(x) we subtract the common terms. So


(f-g)(x)

(f-g)(-4)

We replace x by -4

(f-g)(-4) = -151
I drew a picture!!
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Maybe you didn't.
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I like to picture things though.
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Ok, a rectangle cut in half.
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Ok, by definition of "half," just multiply the number of rectangles by 2.
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1 x 2 = 2 after cutting the brownies in half.
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2 x 2 = 4 after cutting it in half again.
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4 rectangles now!!
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Doing it the other way... pretend you are starting over from scratch.
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A new batch of brownies!
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But still pay attention to what you already cut.
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Cut down the middle the other direction.
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What's 4 x 2?
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8.
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Now, finally, we multiply the half of the half brownies.
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What's 8 x 2?
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16.
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16 slices.
Interest is found as the principal times the percentage rate / 100, divided by the proportion of the days. This is, if r is the percentage rate for 1 year, n is the number of days, and p is the amount invested you can calculate the interests as p* (r%/100) * n/365 = $600 * (8/100) * 45/365 = $5.92. So<span> the answer is the option D. 5.92. </span>