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lys-0071 [83]
3 years ago
9

Jerome has 1/4 of the group's video games at his house. Mario has 2/5 of the video games at his house. what fraction of the grou

p video games is either at Jerome's house or Mario's house?
Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer: 13/20 of the video games at both of their houses.


Step-by-step explanation: The equation is 1/4 + 2/5. You need to find their common denominator which is 20, so the equation is now 5/20 + 8/20 = 13/20, which can't be simplified.


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Solve this system of equations using the substitution method.
Bingel [31]

Answer:

x = 1.2

y = 6.6

Step-by-step explanation:

1) y= -2x+9

2) 8x-3=y

Substitute y in equation 1 using y in equation 2.

8x - 3 = -2x + 9

+ 3 on both sides

8x = -2x + 12

+ 2x on both sides

10x = 12

x = 1.2

To find y, plug in x

8x - 3 = y

9.6 - 3 = y

6.6 = y

Hope this helps :)

5 0
3 years ago
HELP ASAP PLEASE 3 extra points if you get it right
-BARSIC- [3]
It would be the origin
8 0
3 years ago
Read 2 more answers
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
Jamiyah and Samantha went to a grocery store and purchased a bag of 15 apples. Let x represent the Jamiyah’s portion of the appl
belka [17]

Answer:

xy=15

Step-by-step explanation:

3 0
3 years ago
Use the information given to enter an equation in standard form. Slope is 4/7 , and (5,8) is on the line.
aalyn [17]
8=4/7(7) + b
b=4
Y= 4/7 x + 4
[You might wanna check your answer, I might be wrong. Sorry if I’m wrong.]
4 0
3 years ago
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