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lys-0071 [83]
3 years ago
9

Jerome has 1/4 of the group's video games at his house. Mario has 2/5 of the video games at his house. what fraction of the grou

p video games is either at Jerome's house or Mario's house?
Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer: 13/20 of the video games at both of their houses.


Step-by-step explanation: The equation is 1/4 + 2/5. You need to find their common denominator which is 20, so the equation is now 5/20 + 8/20 = 13/20, which can't be simplified.


You might be interested in
Los lados de un triángulo rectángulo tienen por medida tres números enteros consecutivos. Calcula los lados del triángulo.
elixir [45]

Answer:

Los lados del triángulo rectángulo miden 3, 4 y 5, respectivamente.

Step-by-step explanation:

Un triángulo rectángulo puede ser descrito mediante el teorema de Pitágoras, para el caso de tres lados representando tres números enteros consecutivos, tenemos que:

(n+2)^{2} = n^{2} + (n+1)^{2} (1)

Donde n es un número natural.

A continuación, expandimos la expresión y resolvemos:

n^{2}+4\cdot n +4 = n^{2} + n^{2} +2\cdot n + 1

n^{2}-2\cdot n -3 = 0

(n -3) \cdot (n+1) = 0

La única solución factible es n = 3. En consecuencia, los lados del triángulo rectángulo miden 3, 4 y 5, respectivamente.

4 0
3 years ago
The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
What fracction is closets to -3/5, 2/5 0r 4/5
Andreas93 [3]

Answer:

2/5

Step-by-step explanation:

4 0
3 years ago
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I am in need of help-
ikadub [295]
I think it’s 4.308 when u multiply
4 0
3 years ago
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Is 5 a irrational number
AfilCa [17]

Answer:

no.

Step-by-step explanation:

6 0
3 years ago
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