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vivado [14]
2 years ago
15

Natalie is playing a game using a fair coin. Contestants win the game if the fair coin lands tails up. The theoretical proabaili

ty that the coin will lamd tails is ? If 250 contestants play the game, about of them are expected to win
Mathematics
1 answer:
oee [108]2 years ago
8 0

The theoretical probability of landing on tails is P = 0.5, and out of the 250 contestants, around 125 will win the game.

<h3>About how many contestants will win?</h3>

The coin has two possible outcomes, so if it is a fair coin, the probability for each of the outcomes will be 0.5 (this is the theoretical probability for a fair coin, where all the outcomes have the same probability).

Now, we know that a person wins if the coin lands tails up, and the probability of landing on tails is 0.5

Then, for a sample N, we can expect that about 0.5*N of the participants win.

In this case, the sample is 250, then we can expect that:

0.5*250 = 125

Around 125 of the contestants win the game

If you want to learn more about probability, you can read:

brainly.com/question/251701

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This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


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\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

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