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emmainna [20.7K]
2 years ago
15

Https://pad let.com/chosenmcdonald/m6geceexz50r32nk how does the economy in the 1700s work

Mathematics
1 answer:
PtichkaEL [24]2 years ago
6 0
Mercantilism or laissez faire capitalism
You might be interested in
Jason has $800 more than Paul. Alex has $150 less than Jason. How much more does Alex have than Paul?
jolli1 [7]

Hey there!!

Jason = 800 + Paul

Alex = Jason - 150

How much more does Alex have the Paul?

Let's take the equation of Alex

... Alex = Jason - 150

... Add 150 on both sides

... Alex + 150 = Jason

Now we have the equation for Jason,

... Jason = 800 + Paul , and we got Alex + 150 = Jason

... Now let's plug in the values

... Alex + 150 = 800 + Paul

Subtract 150 on both sides...

Alex = 800 - 150 + Paul

... Alex = 650 + Paul

Now we got the answer for our question :

The answer - Alex has $650 than Paul.

Hope my answer helps!!


4 0
3 years ago
Find the surface area of the cube shown below. units 2 2 squared
ruslelena [56]

The surface area of the cube with a side length of 2 units is 24 units squared

<h3>How to determine the surface area?</h3>

The side length of the cube is given as:

l = 2

The surface area is calculated as:

Surface area = 6l^2

This gives

Surface area = 6 *2^2

Evaluate

Surface area = 24

Hence, the surface area of the cube is 24 unit squared

Read more about surface area at:

brainly.com/question/13175744

#SPJ1

7 0
2 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
Pls answer clearly thank you will be marking smartest correct answer!
balandron [24]

Number 9 is no because if you were to divide that it be a decimal and a decimal is an irrational number.

Number 10 is yes. When divide 2 by 5 you get 0.4 which is a terminating number because it never ends

3 0
2 years ago
What is 6➗2+5+2✖3=24 in parenthesis
Juliette [100K]
(6÷2)+(5+2×3)=24
I got this so this is the answer
  

  ;D
5 0
3 years ago
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