The rice will cost $17.6 for serving 40 people
<h3><u>Solution:</u></h3>
We need to determine the cost of serving 40 people with rice
Arborio rice is purchased in 2-pound boxes for $1.99
The price of 1 pound box will be 
1 Pound (lb) is equal to 16 ounces (oz)
Therefore, the price of 16 ounces is $0.995
A cup of raw Arborio rice weighs 7 ounces and it serve 1 people

Therefore rice will cost $17.6 for serving 40 people
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
I did the math and <span>x=116</span>
Answer:
g = -18/7
This is the exact form of the answer
Answer:
The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.
Step-by-step explanation:
We have these following rates of type II diabetes:
7% among Caucasians
10% among African-Americans
12% among Hispanics
5% among Asian-Americans.
The ethnic distribution of Houston is:
30% Caucasian
25% African-American
40% Hispanic
5% Asian-American
What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.


The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.