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2 years ago

15

2. I'm thinking of two positive integers. Their sum is 8. Their product is 12. What are they?

2 answers:

dimulka [17.4K]2 years ago

6 0

Answer:

2 and 6

Step-by-step explanation:

Take integers to be X and Y

X*Y=12

X + Y = 8

from the second equation, X= 8-Y

put X in the first Equation

(8-Y)Y = 12

Expand the equation

-Y² + 8Y - 12 = 0

Factorize the above equation

(-Y + 2) (Y - 6) = 0

Y = 2 and Y = 6

choose any value of Y.

so Y = 6,

put Y in X + Y = 8

X + 6 = 8

X = 2

therefore the integers are 2 and 6

Luba_88 [7]2 years ago

3 0

Answer:

the answer are 2 and 6 ok

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What is the value of hin the figure below? In this diagram, ABAD ~ ACBD.

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2 years ago

Elementary Algebra Skill

mr_godi [17]

The answer is a = $\frac{4}{-3}$

Step-by-step explanation:

<em>1. Convert the mixed fraction to an improper fraction</em>

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

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<em>2. Now the equation is,</em>

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<em>3. Take LCM on both sides. </em>

For the left side, multiply the first fraction by $\frac{3}{3}$ and multiply the second fraction by $\frac{2}{2}$

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<em>4. Solve by making a the subject</em>

$\frac{9a-8a}{6}$ = $\frac{10+8a}{3}$

$\frac{a}{6}$ = $\frac{10+8a}{3}$

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Keyword: Equations

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3 years ago

Can anyone help please

skelet666 [1.2K]

A-4b that’s my answer hope this help

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3 years ago